anonymous
  • anonymous
How do I solve dy/dx = (y-1)^2? y(0)=1
Mathematics
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anonymous
  • anonymous
How do I solve dy/dx = (y-1)^2? y(0)=1
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
dy/(y-1)^2 = dx -1/(y-1) = x+c
anonymous
  • anonymous
yd/dx (y-1 ^ 2 ) = (y-1)^(2-1) y(0) = 0-1 = -1 !
anonymous
  • anonymous
this must be wrong///

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anonymous
  • anonymous
it must be dx/dy instead of dy/dx
anonymous
  • anonymous
my teacher mentioned this type of problem
anonymous
  • anonymous
-1/(x+c) = y-1 y=(x+c-1)/(x+c) now put the values 0,1 c-1/c = 0 c=1
anonymous
  • anonymous
there you go
anonymous
  • anonymous
thank you
anonymous
  • anonymous
click on good answer to complete my century plz ;)
anonymous
  • anonymous
thnx

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