anonymous
  • anonymous
How do I solve dy/dx = (y-1)^2? y(0)=1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
dy/(y-1)^2 = dx -1/(y-1) = x+c
anonymous
  • anonymous
yd/dx (y-1 ^ 2 ) = (y-1)^(2-1) y(0) = 0-1 = -1 !
anonymous
  • anonymous
this must be wrong///

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anonymous
  • anonymous
it must be dx/dy instead of dy/dx
anonymous
  • anonymous
my teacher mentioned this type of problem
anonymous
  • anonymous
-1/(x+c) = y-1 y=(x+c-1)/(x+c) now put the values 0,1 c-1/c = 0 c=1
anonymous
  • anonymous
there you go
anonymous
  • anonymous
thank you
anonymous
  • anonymous
click on good answer to complete my century plz ;)
anonymous
  • anonymous
thnx

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