Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

what will be the integration of 1/(1+x²)½ along x?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[\int\limits 1/(1+x ^{2})^{1/2}\] it will be \[\ln (1 + x ^{2})^{1/2}\]
you know that when the numerator is the derivative of the dominator then the integration is ln "dominator" :)
but the derivative of denominator should be there in the numerator

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[x= \tan \theta\]
ok , the derivative of (x^2 )^1/2 is 1/2 (2x) so 2 cancel the other 2 :)
and for natural log, exponent should be 1
\[\int\limits 1/x= \ln x\]
if the exponent is other than 1, we use power rule
yeah but we can't multiply it with 2x so ln(1+x²)½ is not the right answer
\[d x= \sec^2 \theta d \theta\]
i think its correct .. anyways good luck ..
\[\int\limits \sec^2 \theta/(\sqrt{1+\tan^2 \theta} )\]
\[\int\limits \sec^2\theta/\sec \theta d \theta\]
\[\int\limits \sec \theta d \theta\]
\[\ln (\sec \theta + \tan \theta) +C\]
by backward substitution \[\tan \theta =x\]
yeah that will give us integration of secθ that is ln(secθ+tanθ) and by substituting and we will get probably get ln(sec(tan^-x)+x)
\[\sec \theta =\sqrt{1+x^2}\]
thanks for the help i have some questions on multiple integral usage in finding area and volume. Anyone please help me
post it as a new Q,some one would surly look at it :)
Uzma are you from Pakistan?
ahaa ! ok waiting ur new Qs :)
yes :)
Can you please tell me your qualification and city
what would u do with that :)
nothing just to guess the level of your understanding mathematics
mathematics is as vast, that one can hardly grasp even one area

Not the answer you are looking for?

Search for more explanations.

Ask your own question