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anonymous

  • 5 years ago

Somebody please help me with a: False point method for solution of equations Question (A-level U.K. maths)

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    The second half of the question..

  3. anonymous
    • 5 years ago
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    x = (0f(1) - 1f(0))/(f(0)-f(1))

  4. amistre64
    • 5 years ago
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    false point method? dont they call that Newtons approximation?

  5. anonymous
    • 5 years ago
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    all i could get

  6. amistre64
    • 5 years ago
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    x^5 -5x +1; if we pick x=2 perhaps; then we want the equation of the tangelnt line at x=2 (2,23) 5(2)^4 -5 = 75 23 - 7(2) = b y = 75x + 9 = 0 when x = -75/9 = -8' 1/3 did I do it right?

  7. anonymous
    • 5 years ago
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    you have to use the function of 1 and 0 because they have opposite signs and therefore straddle the root, a line is constructed inbetweeen them to get a new approximation of x, but what you did for newton raphsons method is right! :) im not sure if my workings are correct...

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