anonymous
  • anonymous
Somebody please help me with a: False point method for solution of equations Question (A-level U.K. maths)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
The second half of the question..
anonymous
  • anonymous
x = (0f(1) - 1f(0))/(f(0)-f(1))

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amistre64
  • amistre64
false point method? dont they call that Newtons approximation?
anonymous
  • anonymous
all i could get
amistre64
  • amistre64
x^5 -5x +1; if we pick x=2 perhaps; then we want the equation of the tangelnt line at x=2 (2,23) 5(2)^4 -5 = 75 23 - 7(2) = b y = 75x + 9 = 0 when x = -75/9 = -8' 1/3 did I do it right?
anonymous
  • anonymous
you have to use the function of 1 and 0 because they have opposite signs and therefore straddle the root, a line is constructed inbetweeen them to get a new approximation of x, but what you did for newton raphsons method is right! :) im not sure if my workings are correct...

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