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AbdulRehman
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find the volume enclosed by x²+y²=4 and z=x+4y using multiple integrals?
 3 years ago
 3 years ago
AbdulRehman Group Title
find the volume enclosed by x²+y²=4 and z=x+4y using multiple integrals?
 3 years ago
 3 years ago

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rim182946 Group TitleBest ResponseYou've already chosen the best response.1
I think you need more information like z = 0 ( so it can be above the xy plane )
 3 years ago

AbdulRehman Group TitleBest ResponseYou've already chosen the best response.0
Then find the area only in first ocatne
 3 years ago

rim182946 Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{0}^{\pi/2}\int\limits_{0}^{2}\int\limits_{0}^{r \cos \theta+4r \sin \theta}rdzdrd \theta\]
 3 years ago

rim182946 Group TitleBest ResponseYou've already chosen the best response.1
you should use cyindrical because the region in the xy plane is circular in nature you have to convert the z bounds then the low z bound is z = 0 and the high z bound is z = x + 4y you said only the first octant so after the z integration you are down to the quarter circle in the first quadrant which has r bounds r = 0 to r = 2 (the circle of radius 2 centered at the origin) theta bounds of theta = o to theta = Pi/2
 3 years ago

AbdulRehman Group TitleBest ResponseYou've already chosen the best response.0
Well that is quite right. I find difficulty in drawing graph in 3d through and then finding it's limit. Any guess.
 3 years ago
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