anonymous
  • anonymous
The circle intersects the line with he equation x+y=3 at 2 points, A and B. Find algebraically the coordinates A and B show the distance AB= sqrt 162 thanks :)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
what line?
anonymous
  • anonymous
a circle equation has an equation of x6@+y^2=45 is that what you mean?
anonymous
  • anonymous
MissMys, you just wrote something in the comments? is that more info about this problem?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yes :)
anonymous
  • anonymous
Well you have to write the whole question word for word as i was given to you, in order for us to be of any help.
anonymous
  • anonymous
a circle equation has an equation of x^2+y^2=45 The circle intersects the line with he equation x+y=3 at 2 points, A and B. Find algebraically the coordinates A and B show that the distance AB is sqrt 162 and the previous qs asks about radius and centre of the circle
anonymous
  • anonymous
Put the two equations together, you would find to values for y=3, y=34. You can use these values to obtain related values for x. The two x,y values should be point A and B. You can double check it with distance formula.
anonymous
  • anonymous
sorry but i dont understand? :S so do i put those two values into the equation??
anonymous
  • anonymous
You have your equation for the line, you can solve for x, or y. From your line equation, x=3-y. Put this in the circle equation. (3-y)^2+y^2=45. I have already done this much for you, the result is y=3, y=34
anonymous
  • anonymous
urm, i havent got a clue what you did and 34 is wrong :S i am so dead tomorrow :(
anonymous
  • anonymous
i understand the first bit then confused of how you got 3 and 34 :S
anonymous
  • anonymous
Well forget about 3 and 34. Solve for y from the new equation created.
anonymous
  • anonymous
thanks for helping but i cant do it :( ill still give u the medal :)
anonymous
  • anonymous
What can't you do? You have an equation (3-y)^2+y^2=45, solve for y.
anonymous
  • anonymous
yea i dunno what or how you do the squared bit :(
anonymous
  • anonymous
\[(3-y)^{2}=(3-y)(3-y)\]
anonymous
  • anonymous
thanks :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.