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anonymous

  • 5 years ago

The circle intersects the line with he equation x+y=3 at 2 points, A and B. Find algebraically the coordinates A and B show the distance AB= sqrt 162 thanks :)

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  1. anonymous
    • 5 years ago
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    what line?

  2. anonymous
    • 5 years ago
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    a circle equation has an equation of x6@+y^2=45 is that what you mean?

  3. anonymous
    • 5 years ago
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    MissMys, you just wrote something in the comments? is that more info about this problem?

  4. anonymous
    • 5 years ago
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    yes :)

  5. anonymous
    • 5 years ago
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    Well you have to write the whole question word for word as i was given to you, in order for us to be of any help.

  6. anonymous
    • 5 years ago
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    a circle equation has an equation of x^2+y^2=45 The circle intersects the line with he equation x+y=3 at 2 points, A and B. Find algebraically the coordinates A and B show that the distance AB is sqrt 162 and the previous qs asks about radius and centre of the circle

  7. anonymous
    • 5 years ago
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    Put the two equations together, you would find to values for y=3, y=34. You can use these values to obtain related values for x. The two x,y values should be point A and B. You can double check it with distance formula.

  8. anonymous
    • 5 years ago
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    sorry but i dont understand? :S so do i put those two values into the equation??

  9. anonymous
    • 5 years ago
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    You have your equation for the line, you can solve for x, or y. From your line equation, x=3-y. Put this in the circle equation. (3-y)^2+y^2=45. I have already done this much for you, the result is y=3, y=34

  10. anonymous
    • 5 years ago
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    urm, i havent got a clue what you did and 34 is wrong :S i am so dead tomorrow :(

  11. anonymous
    • 5 years ago
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    i understand the first bit then confused of how you got 3 and 34 :S

  12. anonymous
    • 5 years ago
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    Well forget about 3 and 34. Solve for y from the new equation created.

  13. anonymous
    • 5 years ago
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    thanks for helping but i cant do it :( ill still give u the medal :)

  14. anonymous
    • 5 years ago
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    What can't you do? You have an equation (3-y)^2+y^2=45, solve for y.

  15. anonymous
    • 5 years ago
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    yea i dunno what or how you do the squared bit :(

  16. anonymous
    • 5 years ago
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    \[(3-y)^{2}=(3-y)(3-y)\]

  17. anonymous
    • 5 years ago
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    thanks :)

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