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anonymous
 5 years ago
\[p = \sqrt{2  p}\]
anonymous
 5 years ago
\[p = \sqrt{2  p}\]

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could you better yet show me how to do them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0p=sqrt(2p) First, square both sides. p²=2p Then, throw everything to one side. p²+p2=0 Then, factor it. (p+2)(p1)=0 p+2=0 or p1=0 p=2 or p=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this goes against every rule in algebra so far. my teacher gave every one F's because he thinks we cant learn _

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(4) does not equal 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0waiit so what is the other one?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0p=2 is wrong, since sqrt(2p) can't become lower than 2.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0only 1; when squareing sides, you run the risk of getting a false answer and have to check it back into the original to see if it works :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then it is any number greater than 2?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(2p) shouldnt go below zero; below 2 is fine :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(22) = sqrt(4) = 2 2 <> 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok... this is confusing

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what is confusing about it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just the way my teacher told us only to do it a way i dont remember and like coding learn 2 at once you get raped... :/

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there are only two numbers whose value equals their sqrts; do you know those numbers?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0for any number.... does 0 = sqrt(0) ?? does 1 = sqrt(1) ??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no sqrt for 1 0 = \[\sqrt{0}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01*1 = 1 ; therefore; sqrt(1) = 1 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldnt it equal \[\sqrt{1}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01 = 1*1 = sqrt(1) = 1/1 = .....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0p = sqrt(2p) what should we do to solve this?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0staring at it wont help :) Try something, even if its wrong....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh the question marks should be sqrd

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its a good attempt; but how do we 'do the same thing' to the other side of the equals?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how do we 'undo' a square root?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes; so lets try that :) to both sides

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0p^2 = sqrt(2p)^2 p^2 = 2p

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0do you see that steps I did?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when you square the squarroot; sign; it disappears; that is the only thing that happens to that part....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(15)^2 = 15 sqrt(3)^2 = 3 sqrt(23654)^2 = 23654 see it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sqrt(2p)^2 = 2p right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0p^2 = 2p ; what do you wanna do to this to solve for p?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ok...lets put it all to the same side.... p^2 +p 2 = 22p+p p^2 +p 2 = 0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how do we 'unFOIL' this ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0huhm flutter if i know.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0please dont use that language here

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i never understood the foil. my teacher writes it on the bored and says his thought erases then goes to the next prob

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0FOIL is a term that is used to teach people how to multiply stuff inside of paranthesis

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0they teach it in hopes that it will mean something later on; but really its a crutch that keeps you from learning whats really happening to a problem

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0The distributive property is all that we need; do you remember the distributive property?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i ask for help bet he says a smart alic reply to me... he needs a different career

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0How do we use the distributive property then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0times outside the ( ) by the inside of the ( )

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0very good :) We can do that as many times as it takes.... watch: Do you agree that 8*3 = 24?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then 3(5+3) should also equal 24 right? 3(5) + 3(3) = 24 15 + 9 = 24 24 = 24

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and... (1+2)(5+3) should also equal 24..like this: (1+2)(5) + (1+2)(3) = 24 5(1) + 5(2) + 3(1) + 3(2) = 24 5 + 10 + 3 + 6 = 24 15 + 9 = 24 24 = 24 that is what they are calling FOIL..... its just using the distributive property twice

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so foil = complete distribution?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok.. u got a mic or something for pc? this would be easier...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0nope; using college computers..no sound no video no nothing but a keyboard

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0darn... ok so please guide me through the problem im about to make a new post... itl be easier...
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