anonymous
  • anonymous
\[p = \sqrt{2 - p}\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
could you better yet show me how to do them?
anonymous
  • anonymous
p=sqrt(2-p) First, square both sides. p²=2-p Then, throw everything to one side. p²+p-2=0 Then, factor it. (p+2)(p-1)=0 p+2=0 or p-1=0 p=-2 or p=1
anonymous
  • anonymous
this goes against every rule in algebra so far. my teacher gave every one F's because he thinks we cant learn -_-

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More answers

amistre64
  • amistre64
sqrt(4) does not equal -2
anonymous
  • anonymous
I wasn't done yet.
amistre64
  • amistre64
1 is good
anonymous
  • anonymous
waiit so what is the other one?
anonymous
  • anonymous
2
anonymous
  • anonymous
p=-2 is wrong, since sqrt(2-p) can't become lower than 2.
amistre64
  • amistre64
only 1; when squareing sides, you run the risk of getting a false answer and have to check it back into the original to see if it works :)
anonymous
  • anonymous
so then it is any number greater than 2?
amistre64
  • amistre64
sqrt(2-p) shouldnt go below zero; below 2 is fine :)
amistre64
  • amistre64
sqrt(2--2) = sqrt(4) = 2 -2 <> 2
anonymous
  • anonymous
ok... this is confusing
amistre64
  • amistre64
what is confusing about it?
anonymous
  • anonymous
just the way my teacher told us only to do it a way i dont remember and like coding learn 2 at once you get raped... :/
amistre64
  • amistre64
there are only two numbers whose value equals their sqrts; do you know those numbers?
anonymous
  • anonymous
for this one?
amistre64
  • amistre64
for any number.... does 0 = sqrt(0) ?? does 1 = sqrt(1) ??
anonymous
  • anonymous
no sqrt for 1 0 = \[\sqrt{0}\]
amistre64
  • amistre64
1*1 = 1 ; therefore; sqrt(1) = 1 right?
anonymous
  • anonymous
wouldnt it equal \[\sqrt{1}\]
amistre64
  • amistre64
1 = 1*1 = sqrt(1) = 1/1 = .....
amistre64
  • amistre64
p = sqrt(2-p) what should we do to solve this?
anonymous
  • anonymous
i dont even know. :/
amistre64
  • amistre64
staring at it wont help :) Try something, even if its wrong....
anonymous
  • anonymous
give me a minute...
anonymous
  • anonymous
\[-2^{?} +p ^{?}\]
anonymous
  • anonymous
ohh the question marks should be sqrd
amistre64
  • amistre64
its a good attempt; but how do we 'do the same thing' to the other side of the equals?
amistre64
  • amistre64
how do we 'undo' a square root?
anonymous
  • anonymous
square it
amistre64
  • amistre64
yes; so lets try that :) to both sides
amistre64
  • amistre64
p^2 = sqrt(2-p)^2 p^2 = 2-p
anonymous
  • anonymous
4 + psqrd = 0?
amistre64
  • amistre64
do you see that steps I did?
anonymous
  • anonymous
yes
amistre64
  • amistre64
when you square the squarroot; sign; it disappears; that is the only thing that happens to that part....
anonymous
  • anonymous
ok
amistre64
  • amistre64
sqrt(15)^2 = 15 sqrt(3)^2 = 3 sqrt(23654)^2 = 23654 see it?
amistre64
  • amistre64
sqrt(2-p)^2 = 2-p right?
anonymous
  • anonymous
yeah
amistre64
  • amistre64
p^2 = 2-p ; what do you wanna do to this to solve for p?
anonymous
  • anonymous
same side?
amistre64
  • amistre64
ok...lets put it all to the same side.... p^2 +p -2 = 2-2-p+p p^2 +p -2 = 0
anonymous
  • anonymous
ok
amistre64
  • amistre64
how do we 'unFOIL' this ?
anonymous
  • anonymous
huhm flutter if i know.
amistre64
  • amistre64
please dont use that language here
anonymous
  • anonymous
kk
anonymous
  • anonymous
i never understood the foil. my teacher writes it on the bored and says his thought erases then goes to the next prob
amistre64
  • amistre64
FOIL is a term that is used to teach people how to multiply stuff inside of paranthesis
anonymous
  • anonymous
ok
amistre64
  • amistre64
they teach it in hopes that it will mean something later on; but really its a crutch that keeps you from learning whats really happening to a problem
amistre64
  • amistre64
The distributive property is all that we need; do you remember the distributive property?
anonymous
  • anonymous
i ask for help bet he says a smart alic reply to me... he needs a different career
anonymous
  • anonymous
yeah
amistre64
  • amistre64
How do we use the distributive property then?
anonymous
  • anonymous
times outside the ( ) by the inside of the ( )
amistre64
  • amistre64
very good :) We can do that as many times as it takes.... watch: Do you agree that 8*3 = 24?
anonymous
  • anonymous
yep
amistre64
  • amistre64
then 3(5+3) should also equal 24 right? 3(5) + 3(3) = 24 15 + 9 = 24 24 = 24
anonymous
  • anonymous
ok
amistre64
  • amistre64
and... (1+2)(5+3) should also equal 24..like this: (1+2)(5) + (1+2)(3) = 24 5(1) + 5(2) + 3(1) + 3(2) = 24 5 + 10 + 3 + 6 = 24 15 + 9 = 24 24 = 24 that is what they are calling FOIL..... its just using the distributive property twice
anonymous
  • anonymous
ok so foil = complete distribution?
amistre64
  • amistre64
yes :)
anonymous
  • anonymous
ok.. u got a mic or something for pc? this would be easier...
amistre64
  • amistre64
nope; using college computers..no sound no video no nothing but a keyboard
anonymous
  • anonymous
darn... ok so please guide me through the problem im about to make a new post... itl be easier...
amistre64
  • amistre64
ok...
anonymous
  • anonymous
i posted it...

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