## anonymous 5 years ago $p = \sqrt{2 - p}$

1. anonymous

could you better yet show me how to do them?

2. anonymous

p=sqrt(2-p) First, square both sides. p²=2-p Then, throw everything to one side. p²+p-2=0 Then, factor it. (p+2)(p-1)=0 p+2=0 or p-1=0 p=-2 or p=1

3. anonymous

this goes against every rule in algebra so far. my teacher gave every one F's because he thinks we cant learn -_-

4. amistre64

sqrt(4) does not equal -2

5. anonymous

I wasn't done yet.

6. amistre64

1 is good

7. anonymous

waiit so what is the other one?

8. anonymous

2

9. anonymous

p=-2 is wrong, since sqrt(2-p) can't become lower than 2.

10. amistre64

only 1; when squareing sides, you run the risk of getting a false answer and have to check it back into the original to see if it works :)

11. anonymous

so then it is any number greater than 2?

12. amistre64

sqrt(2-p) shouldnt go below zero; below 2 is fine :)

13. amistre64

sqrt(2--2) = sqrt(4) = 2 -2 <> 2

14. anonymous

ok... this is confusing

15. amistre64

16. anonymous

just the way my teacher told us only to do it a way i dont remember and like coding learn 2 at once you get raped... :/

17. amistre64

there are only two numbers whose value equals their sqrts; do you know those numbers?

18. anonymous

for this one?

19. amistre64

for any number.... does 0 = sqrt(0) ?? does 1 = sqrt(1) ??

20. anonymous

no sqrt for 1 0 = $\sqrt{0}$

21. amistre64

1*1 = 1 ; therefore; sqrt(1) = 1 right?

22. anonymous

wouldnt it equal $\sqrt{1}$

23. amistre64

1 = 1*1 = sqrt(1) = 1/1 = .....

24. amistre64

p = sqrt(2-p) what should we do to solve this?

25. anonymous

i dont even know. :/

26. amistre64

staring at it wont help :) Try something, even if its wrong....

27. anonymous

give me a minute...

28. anonymous

$-2^{?} +p ^{?}$

29. anonymous

ohh the question marks should be sqrd

30. amistre64

its a good attempt; but how do we 'do the same thing' to the other side of the equals?

31. amistre64

how do we 'undo' a square root?

32. anonymous

square it

33. amistre64

yes; so lets try that :) to both sides

34. amistre64

p^2 = sqrt(2-p)^2 p^2 = 2-p

35. anonymous

4 + psqrd = 0?

36. amistre64

do you see that steps I did?

37. anonymous

yes

38. amistre64

when you square the squarroot; sign; it disappears; that is the only thing that happens to that part....

39. anonymous

ok

40. amistre64

sqrt(15)^2 = 15 sqrt(3)^2 = 3 sqrt(23654)^2 = 23654 see it?

41. amistre64

sqrt(2-p)^2 = 2-p right?

42. anonymous

yeah

43. amistre64

p^2 = 2-p ; what do you wanna do to this to solve for p?

44. anonymous

same side?

45. amistre64

ok...lets put it all to the same side.... p^2 +p -2 = 2-2-p+p p^2 +p -2 = 0

46. anonymous

ok

47. amistre64

how do we 'unFOIL' this ?

48. anonymous

huhm flutter if i know.

49. amistre64

please dont use that language here

50. anonymous

kk

51. anonymous

i never understood the foil. my teacher writes it on the bored and says his thought erases then goes to the next prob

52. amistre64

FOIL is a term that is used to teach people how to multiply stuff inside of paranthesis

53. anonymous

ok

54. amistre64

they teach it in hopes that it will mean something later on; but really its a crutch that keeps you from learning whats really happening to a problem

55. amistre64

The distributive property is all that we need; do you remember the distributive property?

56. anonymous

i ask for help bet he says a smart alic reply to me... he needs a different career

57. anonymous

yeah

58. amistre64

How do we use the distributive property then?

59. anonymous

times outside the ( ) by the inside of the ( )

60. amistre64

very good :) We can do that as many times as it takes.... watch: Do you agree that 8*3 = 24?

61. anonymous

yep

62. amistre64

then 3(5+3) should also equal 24 right? 3(5) + 3(3) = 24 15 + 9 = 24 24 = 24

63. anonymous

ok

64. amistre64

and... (1+2)(5+3) should also equal 24..like this: (1+2)(5) + (1+2)(3) = 24 5(1) + 5(2) + 3(1) + 3(2) = 24 5 + 10 + 3 + 6 = 24 15 + 9 = 24 24 = 24 that is what they are calling FOIL..... its just using the distributive property twice

65. anonymous

ok so foil = complete distribution?

66. amistre64

yes :)

67. anonymous

ok.. u got a mic or something for pc? this would be easier...

68. amistre64

nope; using college computers..no sound no video no nothing but a keyboard

69. anonymous

darn... ok so please guide me through the problem im about to make a new post... itl be easier...

70. amistre64

ok...

71. anonymous

i posted it...