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could you better yet show me how to do them?

sqrt(4) does not equal -2

I wasn't done yet.

1 is good

waiit so what is the other one?

p=-2 is wrong, since sqrt(2-p) can't become lower than 2.

so then it is any number greater than 2?

sqrt(2-p) shouldnt go below zero; below 2 is fine :)

sqrt(2--2) = sqrt(4) = 2
-2 <> 2

ok... this is confusing

what is confusing about it?

there are only two numbers whose value equals their sqrts; do you know those numbers?

for this one?

for any number....
does 0 = sqrt(0) ??
does 1 = sqrt(1) ??

no sqrt for 1
0 = \[\sqrt{0}\]

1*1 = 1 ; therefore; sqrt(1) = 1 right?

wouldnt it equal \[\sqrt{1}\]

1 = 1*1 = sqrt(1) = 1/1 = .....

p = sqrt(2-p) what should we do to solve this?

i dont even know. :/

staring at it wont help :)
Try something, even if its wrong....

give me a minute...

\[-2^{?} +p ^{?}\]

ohh the question marks should be sqrd

its a good attempt; but how do we 'do the same thing' to the other side of the equals?

how do we 'undo' a square root?

square it

yes; so lets try that :) to both sides

p^2 = sqrt(2-p)^2
p^2 = 2-p

4 + psqrd = 0?

do you see that steps I did?

yes

ok

sqrt(15)^2 = 15
sqrt(3)^2 = 3
sqrt(23654)^2 = 23654
see it?

sqrt(2-p)^2 = 2-p right?

yeah

p^2 = 2-p ; what do you wanna do to this to solve for p?

same side?

ok...lets put it all to the same side....
p^2 +p -2 = 2-2-p+p
p^2 +p -2 = 0

ok

how do we 'unFOIL' this ?

huhm flutter if i know.

please dont use that language here

kk

FOIL is a term that is used to teach people how to multiply stuff inside of paranthesis

ok

The distributive property is all that we need; do you remember the distributive property?

i ask for help bet he says a smart alic reply to me... he needs a different career

yeah

How do we use the distributive property then?

times outside the ( ) by the inside of the ( )

very good :)
We can do that as many times as it takes.... watch:
Do you agree that 8*3 = 24?

yep

then 3(5+3) should also equal 24 right?
3(5) + 3(3) = 24
15 + 9 = 24
24 = 24

ok

ok
so foil = complete distribution?

yes :)

ok.. u got a mic or something for pc? this would be easier...

nope; using college computers..no sound no video no nothing but a keyboard

darn... ok so please guide me through the problem im about to make a new post... itl be easier...

ok...

i posted it...