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anonymous
 5 years ago
Find the value of Sigma n=1 to infinity n/k^n for k>1
anonymous
 5 years ago
Find the value of Sigma n=1 to infinity n/k^n for k>1

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watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0You already asked this since yesterday. Could you please write down the expression using the nice math symbol so everybody can read the problem correctly?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\[\sum_{n=1}^{\infty}n/k ^{n} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for k>1... I believe k can be replaced with x

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.0\[ \frac{x}{(1x)^2}=\sum_{n=1}^\infty nx^{n} \] Then to compute your series, just substitute \(x=\frac{1}{k}\) to the left hand side :D.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So would it look like 2/k\[4/k^26/k^38/k^4\]?
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