anonymous
  • anonymous
z/1 -1/z =0 is the answer (z,-z)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\frac{z}{1}-\frac{1}{z}=0\] denominator is (1*z) \[z*z= z^{2}\] \[(z^{2}-1)=o\] factor: (x+1)(x-1) =0 z = 1 z = -1 If I deserve medal then give me one.
anonymous
  • anonymous
how do I do that, I am new to this
anonymous
  • anonymous
next to my name click give medal

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anonymous
  • anonymous
di u se/
anonymous
  • anonymous
thank
anonymous
  • anonymous
I think I did it
anonymous
  • anonymous
your welcome
anonymous
  • anonymous
yes, any more question?
anonymous
  • anonymous
yes I do
anonymous
  • anonymous
post it I will try the best
anonymous
  • anonymous
ok
anonymous
  • anonymous
find the LCM y^3 +4y^2 + 4y, y^2-4y
anonymous
  • anonymous
2 question?
anonymous
  • anonymous
no, thats 1
anonymous
  • anonymous
should i post it on the otherside so u can get credit for this as well
anonymous
  • anonymous
\[y^{3}+4y ^{2}+4y \] and another on is : \[y^{2}-4y\]
anonymous
  • anonymous
?
anonymous
  • anonymous
look like u have 2 not 1 ?
anonymous
  • anonymous
the question gives 5 numbers and ask me to find the LCM the way it wants me to answer is number (number)^exponent (y-number)
anonymous
  • anonymous
LCM = 4y
anonymous
  • anonymous
y^3 +4y^2 + 4y= 4y(y^2 +y+1) y^2-4y = 4y(y-1) than LCM is ; 4y
anonymous
  • anonymous
wailt
anonymous
  • anonymous
I'm not sure u may re post question to see some one beter
anonymous
  • anonymous
I can factor nut not sure LCM
anonymous
  • anonymous
no prroblem thanks for trying, I do have something that you may be able to help with
anonymous
  • anonymous
y^3 +4y^2 + 4y = y(y^2+4y+4) = y(y+2)(y+2) =y (y+2)^2 y=0 , y=-2
anonymous
  • anonymous
y^2-4y = y(y-4) y = 0 , y =4
anonymous
  • anonymous
here goes another one x^2-3x+2/x^2+5x-6
anonymous
  • anonymous
it states that i should simplremoving factors of one
anonymous
  • anonymous
I can do this ,give a time I'm slow
anonymous
  • anonymous
ok, lol no problem, and thank u
anonymous
  • anonymous
\[(x^{2}-3x+2)\div(x ^{2}+5x -6)\] I want made suse I'm right?
anonymous
  • anonymous
no not division its factoring
anonymous
  • anonymous
\[\frac{(x-2)(x-1)}{(x+3)(x-2)}\]
anonymous
  • anonymous
no?
anonymous
  • anonymous
x- 2 cancel\[\frac{(x-1)}{(x+3}\]
anonymous
  • anonymous
that right?
anonymous
  • anonymous
i believe so, im horrible at math
anonymous
  • anonymous
I sure it correct
anonymous
  • anonymous
ok, thanx
anonymous
  • anonymous
u r welcom

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