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anonymous
 5 years ago
how do you add radicals
anonymous
 5 years ago
how do you add radicals

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[6\sqrt{2*6\sqrt{8\div6\sqrt[3]{?2}}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0exponential equations? can anyone explain in English?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what the ? means so I'm going to ignore it. What you can do is set that whole expression equal to some value a. Square both sides. Then square them again. Then cube both sides. Now all the radicals are gone and you will have integer exponents on both sides. you should have a^12 on the right. Take the whole thing on the left and raise it to the 1/12 power. That is the value of the expression.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can help you with the steps if you need. Is this what you wanted; a simplified expression?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0allright did my post make sense to you?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not really. I have no Idea what I'm doing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok ill try to type it in the equation editor.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[6\sqrt{2*6\sqrt{8\div \sqrt[3]{2}}}=a\] square both sides \[36*2*6\sqrt{8\div6\sqrt[3]{2}}=a ^{2}\] square both sides again \[36^{2}*2^{2}*6^{2}*8\div6\sqrt[3]{2}=a ^{4}\] cube both sides \[36^{6}*2^{6}*6^{6}*8^{3}/(6^{3}*2)=a^{12}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now just take everything to the 1/12 power

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and you've simplified to just one rational exponent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can simplify it even further than i said by subtracting exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have trouble with the exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know x^a/x^b=x^(ab)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you have two exponential terms with the same base when you multiply them you can add the exponents and when you divide you can subtract the exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\left(6\sqrt{2*6\sqrt{\frac{8}{6\sqrt[3]{2}}}}\right)^2\text{$>$}\left(144\ 2^{5/6} \sqrt{3}\right)^2\text{$>$}124416\ 2^{2/3} \]\[\sqrt[4]{124416\ 2^{2/3}}= 12\ 2^{5/12} 3^{1/4} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Took the original problem expression and deleted the ? mark. Squared the expression and simplified. Squared the result and simplified. Took the fourth root of the last expression to offset the two squares and simplified. Would never attempt this thing without Mathematica executing the book keeping so to speak.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0robtobey and my answers are equivalent

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Think i'll go talk to my teacher tomorrow. I don't understand it. Thank for your help though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0depends on what you think is simplest i geuss though. Allright good luck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0To verify the result, Mathematica reported "True" regarding the assertion that the following expression was valid:\[6\sqrt{2*6\sqrt{\frac{8}{6\sqrt[3]{2}}}}\text{=}12\ 2^{5/12} 3^{1/4} \]
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