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anonymous

  • 5 years ago

how do you add radicals

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  1. anonymous
    • 5 years ago
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    \[6\sqrt{2*6\sqrt{8\div6\sqrt[3]{?2}}}\]

  2. anonymous
    • 5 years ago
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    exponential equations? can anyone explain in English?

  3. anonymous
    • 5 years ago
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    I'm not sure what the ? means so I'm going to ignore it. What you can do is set that whole expression equal to some value a. Square both sides. Then square them again. Then cube both sides. Now all the radicals are gone and you will have integer exponents on both sides. you should have a^12 on the right. Take the whole thing on the left and raise it to the 1/12 power. That is the value of the expression.

  4. anonymous
    • 5 years ago
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    i can help you with the steps if you need. Is this what you wanted; a simplified expression?

  5. anonymous
    • 5 years ago
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    simplify

  6. anonymous
    • 5 years ago
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    allright did my post make sense to you?

  7. anonymous
    • 5 years ago
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    not really. I have no Idea what I'm doing

  8. anonymous
    • 5 years ago
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    ok ill try to type it in the equation editor.

  9. anonymous
    • 5 years ago
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    k

  10. anonymous
    • 5 years ago
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    \[6\sqrt{2*6\sqrt{8\div \sqrt[3]{2}}}=a\] square both sides \[36*2*6\sqrt{8\div6\sqrt[3]{2}}=a ^{2}\] square both sides again \[36^{2}*2^{2}*6^{2}*8\div6\sqrt[3]{2}=a ^{4}\] cube both sides \[36^{6}*2^{6}*6^{6}*8^{3}/(6^{3}*2)=a^{12}\]

  11. anonymous
    • 5 years ago
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    now just take everything to the 1/12 power

  12. anonymous
    • 5 years ago
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    and you've simplified to just one rational exponent

  13. anonymous
    • 5 years ago
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    ok?

  14. anonymous
    • 5 years ago
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    i kind of get it

  15. anonymous
    • 5 years ago
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    you can simplify it even further than i said by subtracting exponents

  16. anonymous
    • 5 years ago
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    k

  17. anonymous
    • 5 years ago
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    I have trouble with the exponents

  18. anonymous
    • 5 years ago
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    do you know x^a/x^b=x^(a-b)

  19. anonymous
    • 5 years ago
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    no

  20. anonymous
    • 5 years ago
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    if you have two exponential terms with the same base when you multiply them you can add the exponents and when you divide you can subtract the exponents

  21. anonymous
    • 5 years ago
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    ok

  22. anonymous
    • 5 years ago
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    x^a*x^b=x^(a+b)

  23. anonymous
    • 5 years ago
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    \[\left(6\sqrt{2*6\sqrt{\frac{8}{6\sqrt[3]{2}}}}\right)^2\text{-$>$}\left(144\ 2^{5/6} \sqrt{3}\right)^2\text{-$>$}124416\ 2^{2/3} \]\[\sqrt[4]{124416\ 2^{2/3}}= 12\ 2^{5/12} 3^{1/4} \]

  24. anonymous
    • 5 years ago
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    Took the original problem expression and deleted the ? mark. Squared the expression and simplified. Squared the result and simplified. Took the fourth root of the last expression to offset the two squares and simplified. Would never attempt this thing without Mathematica executing the book keeping so to speak.

  25. anonymous
    • 5 years ago
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    robtobey and my answers are equivalent

  26. anonymous
    • 5 years ago
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    Think i'll go talk to my teacher tomorrow. I don't understand it. Thank for your help though

  27. anonymous
    • 5 years ago
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    depends on what you think is simplest i geuss though. Allright good luck

  28. anonymous
    • 5 years ago
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    To verify the result, Mathematica reported "True" regarding the assertion that the following expression was valid:\[6\sqrt{2*6\sqrt{\frac{8}{6\sqrt[3]{2}}}}\text{=}12\ 2^{5/12} 3^{1/4} \]

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