what is the hole in G(x)=(x^2-7x+12)/(x-3)

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what is the hole in G(x)=(x^2-7x+12)/(x-3)

Mathematics
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the hole defines the place where the dopmin is restricted and therefore has no value
the hole itself would correspond to the point with an x value of 3
whatever makes the bottoma zero and can be factored out by the top part makes a hole

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