anonymous
  • anonymous
"June is two years older than Sarah, and Sarah is four years younger than Hal. In 4 years, Hal's age will be equal to the sum of the present ages of Sarah and June. Find the age of each." How do I solve this?
Mathematics
chestercat
  • chestercat
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amistre64
  • amistre64
Have you tried yelling at it?
anonymous
  • anonymous
A few times. It's pretty hard headed.
amistre64
  • amistre64
j = s+2 s = h-4 so far :)

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amistre64
  • amistre64
h+4 = j+s
amistre64
  • amistre64
h = s+4 s+4+4 = s+2 + s+4-4
amistre64
  • amistre64
s+8 = 2s +2 6 = s ; but lets dbl chk that lol
amistre64
  • amistre64
j = 8; s = 6; h = 10 to start with in 4 years h = 14 14 = 8+6; got it :)
anonymous
  • anonymous
The question is basically saying: June is 2 years younger than Hal==> J=H-2 Sara is 4 years younger than Hal==>S=H-4 In four years, Hal will be four years older==> H+4 which will be equal to the sum of Sara and June's current age Therefore, H+4=H-2+H-4 Solve for H, You get, 10 Plug in 10 for H in June and Sara's equation from the first year You get: Sara=H-4 = 10-4 = 6 June=H-2 = 10-2 =8

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