the height in feet above ground of water seconds after leaving the mouth of a fountain. THe eqaution is h=-6t^2+12t+10 what is the greatest height the water reaches
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
What you want is the apex of the parabola. There are a couple of ways of finding it. One if you set the derivative equal to 0. The other is rewrite the equation in vertex form:
y = a(x - h)^2 + k
where (h, k) is the vertex
well that doesnt make sense and im pretty sure thats not it
In that case you can also try to graph it using a TI calculator and having the calculator find the maximum value. Which is t = 1 and h = 16. So 1 second after it leaves the mouth of the fountain it attains its maximum height of 16 feet.
Not the answer you are looking for? Search for more explanations.
In order to use the TI you put the equation in under the y = using x for t. Then hit second "CALC" and then option 4 "MAXIMUM" this will have you hit enter on the graph to the left and right of the maximum and then guess where it is. After you do that it will tell you the max.