## toxicsugar22 5 years ago The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.

1. anonymous

use distanace formula to find radius

2. toxicsugar22

Cnu help me

3. anonymous

D from C to P = $\sqrt{3^2+2^2} = \sqrt{13}$ $(x-2)^2 + (y-4)^2 = 13$

4. toxicsugar22

5. anonymous

Yes :D

6. toxicsugar22

i think we write in in slope intecept form

7. toxicsugar22

so what would that be

8. anonymous

You can only write a line in slope-int form, not a circle :D

9. toxicsugar22

ok

10. toxicsugar22

thanks can u help me with this one

11. toxicsugar22

sketch the triangle with vertics A(-5,12), B(4,-2) and C(1,-6) Find the slope of the side AC. Find the slope of the altitude form point B to side AC fIND an equation for the line that includes the altitude from point B to side AC.