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toxicsugar22
 5 years ago
The center of a circle is the point C(2,4), and P(1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.
toxicsugar22
 5 years ago
The center of a circle is the point C(2,4), and P(1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use distanace formula to find radius

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0D from C to P = \[\sqrt{3^2+2^2} = \sqrt{13}\] \[(x2)^2 + (y4)^2 = 13\]

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0ok is this the answer

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0i think we write in in slope intecept form

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0so what would that be

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can only write a line in slopeint form, not a circle :D

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0thanks can u help me with this one

toxicsugar22
 5 years ago
Best ResponseYou've already chosen the best response.0sketch the triangle with vertics A(5,12), B(4,2) and C(1,6) Find the slope of the side AC. Find the slope of the altitude form point B to side AC fIND an equation for the line that includes the altitude from point B to side AC.
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