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toxicsugar22

  • 5 years ago

The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.

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  1. anonymous
    • 5 years ago
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    use distanace formula to find radius

  2. toxicsugar22
    • 5 years ago
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    Cnu help me

  3. anonymous
    • 5 years ago
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    D from C to P = \[\sqrt{3^2+2^2} = \sqrt{13}\] \[(x-2)^2 + (y-4)^2 = 13\]

  4. toxicsugar22
    • 5 years ago
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    ok is this the answer

  5. anonymous
    • 5 years ago
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    Yes :D

  6. toxicsugar22
    • 5 years ago
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    i think we write in in slope intecept form

  7. toxicsugar22
    • 5 years ago
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    so what would that be

  8. anonymous
    • 5 years ago
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    You can only write a line in slope-int form, not a circle :D

  9. toxicsugar22
    • 5 years ago
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    ok

  10. toxicsugar22
    • 5 years ago
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    thanks can u help me with this one

  11. toxicsugar22
    • 5 years ago
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    sketch the triangle with vertics A(-5,12), B(4,-2) and C(1,-6) Find the slope of the side AC. Find the slope of the altitude form point B to side AC fIND an equation for the line that includes the altitude from point B to side AC.

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