"The perimeter of a rectangle is 18 inches. The length is three more than the width. What is the length?" So far I've got: P=18 L+3=W And so I think [(L+3)+w]2=P But I could be wrong...Any takers?

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"The perimeter of a rectangle is 18 inches. The length is three more than the width. What is the length?" So far I've got: P=18 L+3=W And so I think [(L+3)+w]2=P But I could be wrong...Any takers?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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P = 2(L+W)
If you want just one variable (and I think you do) w = L+w means that L = w-3 using daniel's equation P=2((w-3)+w) ya? or 18=2w-6 and then it is easy
2(l+w) = 18 2(w+3+w)=18 since l is w+3 substitute .. 2w+3=9 w=3

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Other answers:

aaak that should be w = L +3 but you knew that
w=3 so l is 6
hi cna u help me after her

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