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- anonymous

A bag contains blue and yellow marbles. Two marbles are drawn without replacement. The probability of selecting a blue marble and then a yellow marble is 0.37, and the probability of selecting a blue marble on the first draw is 0.55.
What is the probability of selecting a yellow marble on the second draw, if the first marble drawn was blue?
A)
18%
B)
20%
C)
46%
D)
67%

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- anonymous

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- anonymous

D) 67%

- anonymous

P(B)*P(Y|B)=.37 P(B)=.55

- anonymous

solve for P(Y|B)

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- gw2011

Let B=Blue
Let Y=Yellow
(B)(Y)=0.37
B=0.55
(0.55)(Y)=0.37
Y=0.37/0.55
Y=0.67=67%
Therefore, the answer is D which is 67%

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