toxicsugar22
  • toxicsugar22
The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Already answered: distance = sqrt (13) Answer: \[(x-2)^2 + (y-4)^2 = 13\]
anonymous
  • anonymous
i think this question asks for tangent line yes? not equation of the circle. need calc.
anonymous
  • anonymous
Lol. I fail. Answer will be up in a second. FORGIVE ME :D

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
slope for CP = 6-4/ -1-2 = -2/3 slope for line (perpendicular to CP) = 3/2 y = mx +b m = 3/2 6 = -3/2 + b; b = 15/2 y = 3x/2 +15/2
anonymous
  • anonymous
oops i fail too! i thought i would have to use implicit diff! F for me.
anonymous
  • anonymous
Lol. Implicit diff would have been hard and it wouldn't have worked :D

Looking for something else?

Not the answer you are looking for? Search for more explanations.