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M

  • 5 years ago

what is ln of -e^-2.40/theta

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  1. anonymous
    • 5 years ago
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    ln e^-x = 1/x

  2. M
    • 5 years ago
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    there is a negative in front of e

  3. M
    • 5 years ago
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    i don't think you can ln a negative

  4. M
    • 5 years ago
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    i'm guessing that negative doesn't matter in my case

  5. M
    • 5 years ago
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    i was hoping it would matter :)

  6. anonymous
    • 5 years ago
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    ln (-(1 / e^2.4) / theta), yea doesnt matter

  7. anonymous
    • 5 years ago
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    Log [-e^(-2.4)/θ] Log [-1/E^(2.4)*θ]] = Log[-0.09071795328941251/θ]

  8. M
    • 5 years ago
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    but you can't log a negative

  9. M
    • 5 years ago
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    -e^x/theta integrate from 2.40 to 0 and set it equal to .520 solve for theta

  10. M
    • 5 years ago
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    -e^2.40/theta - [-e^-0/theta] = .520 -e^-2.40/theta + 1 = .520 e^2.40/theta = .48 -2.40/theta = ln(.48) theta = 3.2699 i was trying to ln the limit 0 at first and that's why i was having problem. yay for perseverance :)

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