M
  • M
what is ln of -e^-2.40/theta
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
ln e^-x = 1/x
M
  • M
there is a negative in front of e
M
  • M
i don't think you can ln a negative

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M
  • M
i'm guessing that negative doesn't matter in my case
M
  • M
i was hoping it would matter :)
anonymous
  • anonymous
ln (-(1 / e^2.4) / theta), yea doesnt matter
anonymous
  • anonymous
Log [-e^(-2.4)/θ] Log [-1/E^(2.4)*θ]] = Log[-0.09071795328941251/θ]
M
  • M
but you can't log a negative
M
  • M
-e^x/theta integrate from 2.40 to 0 and set it equal to .520 solve for theta
M
  • M
-e^2.40/theta - [-e^-0/theta] = .520 -e^-2.40/theta + 1 = .520 e^2.40/theta = .48 -2.40/theta = ln(.48) theta = 3.2699 i was trying to ln the limit 0 at first and that's why i was having problem. yay for perseverance :)

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