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anonymous
 5 years ago
what is ln of e^2.40/theta
anonymous
 5 years ago
what is ln of e^2.40/theta

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is a negative in front of e

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i don't think you can ln a negative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i'm guessing that negative doesn't matter in my case

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was hoping it would matter :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ln ((1 / e^2.4) / theta), yea doesnt matter

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Log [e^(2.4)/θ] Log [1/E^(2.4)*θ]] = Log[0.09071795328941251/θ]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but you can't log a negative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0e^x/theta integrate from 2.40 to 0 and set it equal to .520 solve for theta

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0e^2.40/theta  [e^0/theta] = .520 e^2.40/theta + 1 = .520 e^2.40/theta = .48 2.40/theta = ln(.48) theta = 3.2699 i was trying to ln the limit 0 at first and that's why i was having problem. yay for perseverance :)
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