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anonymous

  • 5 years ago

3=(3x^2y^0z^-4)^-3 I cant have any Zero, negative or fraction exponents.

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  1. anonymous
    • 5 years ago
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    you do not mean 3= do you?

  2. anonymous
    • 5 years ago
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    Yeah ignore that

  3. anonymous
    • 5 years ago
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    Typo

  4. anonymous
    • 5 years ago
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    \[(3x^2y^0z^{-4})^{-3}\]

  5. anonymous
    • 5 years ago
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    Thats exacty how i have it

  6. anonymous
    • 5 years ago
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    multiply all the exponents by -3, ignore the \[y^0\] because it is 1

  7. anonymous
    • 5 years ago
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    \[3^{-3}x^{-6}z^{12}\] ones with negative exponents go down, rest stays up. \[\frac{z^{12}}{3^3x^6}\]

  8. anonymous
    • 5 years ago
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    trick is to not forget the 3. it gets raised to the -3 as well.

  9. anonymous
    • 5 years ago
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    Basic multiplication rules apply? two negatives = posative, + and - = negative?

  10. anonymous
    • 5 years ago
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    *when multiplying exponents

  11. anonymous
    • 5 years ago
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    of course. all normal rules of arithmetic work even when working with exponents.

  12. anonymous
    • 5 years ago
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    One problem I think you did it wrong

  13. anonymous
    • 5 years ago
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    Wait, im confused. How did oyu get 3^-3

  14. anonymous
    • 5 years ago
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    aha i knew it. you have to raise EVERYTHING to the power of -3 because everything was in the parentheses

  15. anonymous
    • 5 years ago
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    Ahah!

  16. anonymous
    • 5 years ago
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    example \[(2x^3y^{-2})^{-2}\] \[=2^{-2}x^{-6}y^4\] dont forget the 2!

  17. anonymous
    • 5 years ago
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    What about X^3 times X^-5

  18. anonymous
    • 5 years ago
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    is it X^-15?

  19. anonymous
    • 5 years ago
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    or X^2

  20. anonymous
    • 5 years ago
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    *X^-2

  21. anonymous
    • 5 years ago
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    \[x^3x^{-5}=x^{3-5}=x^{-2}=\frac{1}{x^2}\]

  22. anonymous
    • 5 years ago
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    dont forget \[x^{-5} = \frac{1}{x^5}\] so \[x^3x^{-5}=\frac{x^3}{x^5}=\frac{1}{x^2}\]\]

  23. anonymous
    • 5 years ago
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    in other words it makes sense to add the exponents when you multiply whether they are positive or negative.

  24. anonymous
    • 5 years ago
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    Only multiply when its an exponent to another power right?

  25. anonymous
    • 5 years ago
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    yup

  26. anonymous
    • 5 years ago
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    \[b^n b^m = b^{n+m}\] \[(b^n)^m=b^{mn}\]

  27. anonymous
    • 5 years ago
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    (-4xy^-5)/(24x^-3) How do i take the recripical of this one?

  28. anonymous
    • 5 years ago
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    \[\frac{-4xy^{-5}}{24x^{-3}}\]

  29. anonymous
    • 5 years ago
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    Correct

  30. anonymous
    • 5 years ago
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    if the exponent is negative move it from down to up or from up to down. do not mess with the coefficients. they have no exponents attached.

  31. anonymous
    • 5 years ago
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    \[\frac{-4xx^3}{24y^5}\]

  32. anonymous
    • 5 years ago
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    now all the exponents are positive. of course you can simplify this: \[-\frac{x^4}{6y^5}\]

  33. anonymous
    • 5 years ago
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    thanks dude

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