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anonymous

  • 5 years ago

derive this! dB/dt= k 100A/rW e^-kt - V

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  1. anonymous
    • 5 years ago
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    im pretty sure its -kte^-kt

  2. anonymous
    • 5 years ago
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    how many variables are there? k,A,r,W and V are constants?

  3. anonymous
    • 5 years ago
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    yeah they're constant, so i thought i could just eliminate

  4. dumbcow
    • 5 years ago
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    is e^-kt in denominator ?

  5. anonymous
    • 5 years ago
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    dB/dt is B'(t) so do you want B"(t)?

  6. dumbcow
    • 5 years ago
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    -k^2(100A/rW)e^-kt

  7. anonymous
    • 5 years ago
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    if k,A,r,W and V are constants and if you are looking for B"(t) then, k100A/rW still stay where is, e^-kt would be -k e^-kt, (t is a variable), and V will just disappear. so your answer would be \[d ^{2}B/d t^{2}=-(k ^{2}100/rW) e ^{-kt}\]

  8. anonymous
    • 5 years ago
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    I forgot the A after the 100 of course, haha... more calculus and DE problems here would be nice...

  9. anonymous
    • 5 years ago
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    ill put some more up then, thanks guys

  10. anonymous
    • 5 years ago
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    hm, maybe tomorrrowws

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