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anonymous
 5 years ago
derive this! dB/dt= k 100A/rW e^kt  V
anonymous
 5 years ago
derive this! dB/dt= k 100A/rW e^kt  V

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im pretty sure its kte^kt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how many variables are there? k,A,r,W and V are constants?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah they're constant, so i thought i could just eliminate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is e^kt in denominator ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dB/dt is B'(t) so do you want B"(t)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if k,A,r,W and V are constants and if you are looking for B"(t) then, k100A/rW still stay where is, e^kt would be k e^kt, (t is a variable), and V will just disappear. so your answer would be \[d ^{2}B/d t^{2}=(k ^{2}100/rW) e ^{kt}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I forgot the A after the 100 of course, haha... more calculus and DE problems here would be nice...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ill put some more up then, thanks guys

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hm, maybe tomorrrowws
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