A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
(a)find y as a function of x, if y'=e^(x1) and y =1 when x=1. What is the y intercept of this curve?
(b)The gradient of a curve is given by y'=e^(2x) and the curve passes through the point (0,1). What is the equation of this curve? What is its horizontal axis?
(c)f=Find y, given that y'=2^(x), and y=1/2log2 when x =0.
(d) It is known that f'(x) = e^x + 1/e and that f(1)=1. Find f(0)
anonymous
 5 years ago
(a)find y as a function of x, if y'=e^(x1) and y =1 when x=1. What is the y intercept of this curve? (b)The gradient of a curve is given by y'=e^(2x) and the curve passes through the point (0,1). What is the equation of this curve? What is its horizontal axis? (c)f=Find y, given that y'=2^(x), and y=1/2log2 when x =0. (d) It is known that f'(x) = e^x + 1/e and that f(1)=1. Find f(0)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits e ^{x1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[1/e \int\limits e^x d x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a) \[y = \int\limits_{}^{} e ^{x1}dx\] u = x1 du = dx \[y=\int\limits_{}^{}e ^{u}du = e ^{u}+C=e ^{x1}+C\] 1=e^0 +C = 1+C C=0 y = e^x1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i actually did (a) i need help with the other ones more lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b) y = e^2x + C 1=e^2 +C C = 1+e^2 \[y = e ^{2x} +e ^{2}+1\] c) y=2^(x)/ln2 +C 1/2ln2 = 1/ln2 +C C = 3/2ln2 \[y = \frac{1}{\ln 2}(2^{x} \frac{3}{2})\] d) f(x) = e^x + x/e +C 1 = e^1 1/e +C C = 1 f(x) =e^x +x/e 1 f(0) = 11 = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for c is it the same as writing y=12^(x)/log2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah well i get 3/2 or 1.5 instead of 1 but yes you could write it either way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats the answer at the back of the book lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahh well book must be wrong..:) is it 1/2*ln2 or 1/(2ln2) for initial conditions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0isnt it the same thing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no one the log is on top the other its on the bottom

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what i thought i dont know what i did wrong on that one...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when i did it i got c=1/2log2 1/2log2 c=1/2log2+1/2log2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0theres should be no negative infront of y=2^(x)/ln2 +C i think lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait is x=0 or x=1 ? no there needs to be a neg because derivative of x = 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh sorry i wrote it wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats it then lol it says 0 above

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah im sorry lol i must of did it by accident lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it happens, keeps me on my toes :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol thanks heaps you made me learn something new today:)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your welcome good luck on the rest

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for question (b) when you sub in x = 1 dont you just get e

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f(x) = e^x + x/e +C when x=1, = e^1 + 1/e +C =1/e  1/e +C =0 + C its not e because e is in denominator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i was looking at d)...is that right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ur answer is right but i tried doing it on my own and got e :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok y=−e^(2−x)+e^2+1 x=1 =e^(2(1)) +e^2 +1 =e^3 +e^2 +1 ahh no you cant combine the e's because of the addition

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh why are you using x=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0omg whats wrong with me lol im not reading any of the questions right im really sorry for troubling you for no reason
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.