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anonymous
 5 years ago
integrate from 0 to 3 x^33x^2+2xdx
anonymous
 5 years ago
integrate from 0 to 3 x^33x^2+2xdx

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watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Is that absolute value?

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1\(x^33x^2+2x=x(x^23x+2)=x(x1)(x2)\) So the integral is equal to \[\int_0^1 x^33x^2+2x\,dx+\int_1^2x^3+3x^22x\,dx+\int_2^3x^33x^2+2x\,dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why did you inverse the sign in the 2nd summation term??

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Because over \([1,2]\) the function \(f(x)=x(x1)(x2)\) is negative. So \(f(x)=f(x)\) on \([1,2]\).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i see... do we have to include 1 and 2?? because you used square brackets to show them

watchmath
 5 years ago
Best ResponseYou've already chosen the best response.1Well, in the integration it won't make any difference whether we have open interval or closed interval.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea thats true.. thanx again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0please check my other question
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