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multiply (2+5i)(5-2i)

Mathematics
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21i
The answer is 20+21i.
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Other answers:

\[(a+bi)(c+di)=(ac-bd)+(ad+bc)i\]
\[2 \times 5 - 5 \times (-2)=20\] \[2 times (-2)+5 \times 5=21\]
so answer is 20 + 20i as agarshna said.
sorry calculation mistake its 20+21i
Multiply through getting 10 +25i-4i-10i^2 Consolidate similar terms: 10+21i-10i^2 Take care of the last term as i^2 us equal to a -1 so the last term is 10 final answer is 21i+20
or placing the real term first: 20+21i
Any questions regarding the procedure for obtaining the solution?

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