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adam124

  • 3 years ago

divide (10-6i)/(2+3i) a.12/13+42/13i b.2/13-42/13i c.5-2i d.3

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  1. satellite73
    • 3 years ago
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    \[\frac{10-6i}{2+3i}=\frac{10-6i}{2+3i}\times \frac{10-6i}{2-3i}\]

  2. AgarshnaMurari
    • 3 years ago
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    Multiply the conjugate of the denominator with the numerator and the denominator

  3. satellite73
    • 3 years ago
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    denominator is \[2^2+3^2=4+9=13\]

  4. satellite73
    • 3 years ago
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    ooops typo my mistake sorry.

  5. ishan_meswani
    • 3 years ago
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    2(5-3i) / (2 +3i) i don't know whats next

  6. satellite73
    • 3 years ago
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    \[\frac{10-6i}{2+3i}\times \frac{2-3i}{2-3i}\]

  7. satellite73
    • 3 years ago
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    denominator is 13 numerator is \[(10-6i)(2-3i)=2-42i\]

  8. satellite73
    • 3 years ago
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    so you get \[\frac{2-42i}{13}=\frac{2}{13}-\frac{42}{13}i\] in standard form

  9. radar
    • 3 years ago
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    38-41i ------- 13

  10. satellite73
    • 3 years ago
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    radar -30-12=-42 i think

  11. radar
    • 3 years ago
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    Yes, I see that I erred. Lost track of signs lol

  12. satellite73
    • 3 years ago
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    and \[-6 \times (-3)=+18\] making the real part 20-18=2

  13. radar
    • 3 years ago
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    I totally agree satellite, please excuse my mistake Adam12.

  14. radar
    • 3 years ago
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    Looks like choice B is the best one.

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