adam124
divide (106i)/(2+3i)
a.12/13+42/13i
b.2/1342/13i
c.52i
d.3



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anonymous
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\[\frac{106i}{2+3i}=\frac{106i}{2+3i}\times \frac{106i}{23i}\]

AgarshnaMurari
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Multiply the conjugate of the denominator with the numerator and the denominator

anonymous
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denominator is \[2^2+3^2=4+9=13\]

anonymous
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ooops typo my mistake sorry.

ishan_meswani
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2(53i) / (2 +3i)
i don't know whats next

anonymous
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\[\frac{106i}{2+3i}\times \frac{23i}{23i}\]

anonymous
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denominator is 13
numerator is \[(106i)(23i)=242i\]

anonymous
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so you get \[\frac{242i}{13}=\frac{2}{13}\frac{42}{13}i\] in standard form

radar
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3841i

13

anonymous
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radar 3012=42 i think

radar
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Yes, I see that I erred. Lost track of signs lol

anonymous
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and \[6 \times (3)=+18\] making the real part 2018=2

radar
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I totally agree satellite, please excuse my mistake Adam12.

radar
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Looks like choice B is the best one.