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anonymous

  • 5 years ago

Arianna kicks a soccer ball off the ground and into the air with an initial velocity of 42 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach?

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  1. anonymous
    • 5 years ago
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    at wht angle to the ground is the ball kicked?

  2. amistre64
    • 5 years ago
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    the angle doesnt matter..... just gotta use the gravity formula... -16t o something

  3. amistre64
    • 5 years ago
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    asuume straight if anything :)

  4. amistre64
    • 5 years ago
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    striaght up... that is

  5. anonymous
    • 5 years ago
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    v=gt t=v/g=4.2seconds s=1/2gt^2=5*4.2^2=88.2feet

  6. myininaya
    • 5 years ago
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    http://www.purplemath.com/modules/quadprob.htm i think this site is helpful for writing formula for velocity

  7. myininaya
    • 5 years ago
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    or i mean height of the ball

  8. myininaya
    • 5 years ago
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    s(t)=-16t^2+42t+0

  9. amistre64
    • 5 years ago
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    s(t) = –G t^2 + V0(t) + H0 Vo = 42 ; H0 = 0; G = 16 s(t) = -16t^2 + 42t s'(t) = -32t + 42 = 0 at 42/32 = 21/16 = 1.3125

  10. myininaya
    • 5 years ago
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    s'(t)=-32t+42 s'(t)=0 when -32t+42=0 so t=42/32=21/16

  11. myininaya
    • 5 years ago
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    lol

  12. amistre64
    • 5 years ago
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    s(t) = -16(1.3125^2) + 42(1.3125) = 27.5625 :) maybe

  13. myininaya
    • 5 years ago
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    k i agree with amistre

  14. amistre64
    • 5 years ago
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    yay!!.... if great minds think alike; what does that leave for idiots lol

  15. myininaya
    • 5 years ago
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    we got something way different from that other guy

  16. amistre64
    • 5 years ago
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    he mighta used the 4.9 meters thing

  17. myininaya
    • 5 years ago
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    ok in this is in feet

  18. myininaya
    • 5 years ago
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    so maybe

  19. anonymous
    • 5 years ago
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    hello all. equation is \[42t-16t^2\] max is when \[t=\frac{-b}{2a}=\frac{21}{16}\] \[42\times \frac{21}{16} -16\times(\frac{21}{16})^2=\frac{441}{16}\]

  20. myininaya
    • 5 years ago
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    we already win :)

  21. anonymous
    • 5 years ago
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    ;)

  22. amistre64
    • 5 years ago
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    yay!!! now if we can only determine that we are not a consensus of fools; I for one have my doubts since I am in it lol

  23. anonymous
    • 5 years ago
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    btw you have to use \[h=h_0+v_0t-16t^2\] because you are working in feet. and you don't need calc to find the vertex of a parabola, although you can

  24. amistre64
    • 5 years ago
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    i did just casue I can :)

  25. myininaya
    • 5 years ago
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    right satelitle! derivatives are just more fun!

  26. anonymous
    • 5 years ago
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    i spose but after getting \[\frac{-b}{2a}\]for the 100th time maybe not.

  27. myininaya
    • 5 years ago
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    i like doing more math than i need to because its just fun lol

  28. amistre64
    • 5 years ago
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    more fun; less mechanical ;)

  29. anonymous
    • 5 years ago
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    on the other hand sometime it is silly to kill a fly with a grenade. you can get the vertex by simple algebra, completing the square or something.

  30. myininaya
    • 5 years ago
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    omg i would love to kill a fly with a grenade how is that not fun

  31. anonymous
    • 5 years ago
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    so not to be argumentative but i would not consider taking the derivative, setting to 0 and solving more or less mechanical than computing the vertex.

  32. myininaya
    • 5 years ago
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    lol ok you do that :)

  33. myininaya
    • 5 years ago
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    i might do it both ways just to show both ways and to do more MATH

  34. anonymous
    • 5 years ago
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    what i need to do is get back to my own work but somehow i keep coming here.

  35. amistre64
    • 5 years ago
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    i know right; it worse than cocaine in here lol

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