anonymous
  • anonymous
For what values of t, if any, is given vector parallel to vector u = (4,-1): (8t, 2t)? and (1,t^2)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
the vector would have to be a scalar of (4,-1) in order to be parallel to it
amistre64
  • amistre64
4 = 8t -1 = 2t
amistre64
  • amistre64
it can also be in the opposit direction and be parallel

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amistre64
  • amistre64
-1/4 is the slope we want to obtain right?
anonymous
  • anonymous
what is it possible?
anonymous
  • anonymous
are you talking about the first one or second?
anonymous
  • anonymous
b/c the second one I got -1/4 and I can't square root it
amistre64
  • amistre64
the second one cant be parallel; there is no hope of a negative slope with it
anonymous
  • anonymous
and the first one I can't get a value that's works because one of them needs to be negative?
amistre64
  • amistre64
thats the way i see it as well; the cant hav the same direction as the original no matter what real values you plug in
anonymous
  • anonymous
okay so the second one doesn't work I can't explain it
anonymous
  • anonymous
I just can't completely find t when I tried
amistre64
  • amistre64
t^2 is always positive; no way to get a negative slope
anonymous
  • anonymous
ohh that's makes more sense thanks!
amistre64
  • amistre64
youre welcome :)
anonymous
  • anonymous
@amistre64: why has the vector be a scalar of (4,-1), it can be any scalar(4x,-1x) isn't it?
anonymous
  • anonymous
allsmiles: is the question asking that both the vectors (8t,2t) and (1,t^2) should be parallel simultaneously or independently?
anonymous
  • anonymous
The first one is always parallel, whatever the value of t be, the second one is parallel (or anti-parallel) when t = +- 1/2
amistre64
  • amistre64
a scalar of (4,-1) simply means that any scalar will do
amistre64
  • amistre64
t<8,2> != x<4,-1> no matter what you do to it right?
amistre64
  • amistre64
they are orthoganal vector
amistre64
  • amistre64
maybe not ortho; but no the same slope :)
anonymous
  • anonymous
sry. what does <> mean?
amistre64
  • amistre64
<> denotes a vector as opposed to () which is a point
amistre64
  • amistre64
<3,5> is a vector; (3,5) is a point
anonymous
  • anonymous
Oh, so for no value of t are any of the two vecs parallel, isnt it?
amistre64
  • amistre64
correct
anonymous
  • anonymous
for \[t \in R\]
amistre64
  • amistre64
the question asked shows point notation; but is assumed to be vectors :)
anonymous
  • anonymous
thanks :)

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