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anonymous
 5 years ago
For what values of t, if any, is given vector parallel to vector u = (4,1): (8t, 2t)? and (1,t^2)?
anonymous
 5 years ago
For what values of t, if any, is given vector parallel to vector u = (4,1): (8t, 2t)? and (1,t^2)?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the vector would have to be a scalar of (4,1) in order to be parallel to it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it can also be in the opposit direction and be parallel

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11/4 is the slope we want to obtain right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you talking about the first one or second?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b/c the second one I got 1/4 and I can't square root it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the second one cant be parallel; there is no hope of a negative slope with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and the first one I can't get a value that's works because one of them needs to be negative?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1thats the way i see it as well; the cant hav the same direction as the original no matter what real values you plug in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so the second one doesn't work I can't explain it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just can't completely find t when I tried

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1t^2 is always positive; no way to get a negative slope

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh that's makes more sense thanks!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre64: why has the vector be a scalar of (4,1), it can be any scalar(4x,1x) isn't it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0allsmiles: is the question asking that both the vectors (8t,2t) and (1,t^2) should be parallel simultaneously or independently?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The first one is always parallel, whatever the value of t be, the second one is parallel (or antiparallel) when t = + 1/2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1a scalar of (4,1) simply means that any scalar will do

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1t<8,2> != x<4,1> no matter what you do to it right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1they are orthoganal vector

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1maybe not ortho; but no the same slope :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry. what does <> mean?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1<> denotes a vector as opposed to () which is a point

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1<3,5> is a vector; (3,5) is a point

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, so for no value of t are any of the two vecs parallel, isnt it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the question asked shows point notation; but is assumed to be vectors :)
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