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anonymous

  • 5 years ago

For what values of t, if any, is given vector parallel to vector u = (4,-1): (8t, 2t)? and (1,t^2)?

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  1. amistre64
    • 5 years ago
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    the vector would have to be a scalar of (4,-1) in order to be parallel to it

  2. amistre64
    • 5 years ago
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    4 = 8t -1 = 2t

  3. amistre64
    • 5 years ago
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    it can also be in the opposit direction and be parallel

  4. amistre64
    • 5 years ago
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    -1/4 is the slope we want to obtain right?

  5. anonymous
    • 5 years ago
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    what is it possible?

  6. anonymous
    • 5 years ago
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    are you talking about the first one or second?

  7. anonymous
    • 5 years ago
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    b/c the second one I got -1/4 and I can't square root it

  8. amistre64
    • 5 years ago
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    the second one cant be parallel; there is no hope of a negative slope with it

  9. anonymous
    • 5 years ago
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    and the first one I can't get a value that's works because one of them needs to be negative?

  10. amistre64
    • 5 years ago
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    thats the way i see it as well; the cant hav the same direction as the original no matter what real values you plug in

  11. anonymous
    • 5 years ago
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    okay so the second one doesn't work I can't explain it

  12. anonymous
    • 5 years ago
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    I just can't completely find t when I tried

  13. amistre64
    • 5 years ago
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    t^2 is always positive; no way to get a negative slope

  14. anonymous
    • 5 years ago
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    ohh that's makes more sense thanks!

  15. amistre64
    • 5 years ago
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    youre welcome :)

  16. anonymous
    • 5 years ago
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    @amistre64: why has the vector be a scalar of (4,-1), it can be any scalar(4x,-1x) isn't it?

  17. anonymous
    • 5 years ago
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    allsmiles: is the question asking that both the vectors (8t,2t) and (1,t^2) should be parallel simultaneously or independently?

  18. anonymous
    • 5 years ago
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    The first one is always parallel, whatever the value of t be, the second one is parallel (or anti-parallel) when t = +- 1/2

  19. amistre64
    • 5 years ago
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    a scalar of (4,-1) simply means that any scalar will do

  20. amistre64
    • 5 years ago
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    t<8,2> != x<4,-1> no matter what you do to it right?

  21. amistre64
    • 5 years ago
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    they are orthoganal vector

  22. amistre64
    • 5 years ago
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    maybe not ortho; but no the same slope :)

  23. anonymous
    • 5 years ago
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    sry. what does <> mean?

  24. amistre64
    • 5 years ago
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    <> denotes a vector as opposed to () which is a point

  25. amistre64
    • 5 years ago
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    <3,5> is a vector; (3,5) is a point

  26. anonymous
    • 5 years ago
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    Oh, so for no value of t are any of the two vecs parallel, isnt it?

  27. amistre64
    • 5 years ago
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    correct

  28. anonymous
    • 5 years ago
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    for \[t \in R\]

  29. amistre64
    • 5 years ago
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    the question asked shows point notation; but is assumed to be vectors :)

  30. anonymous
    • 5 years ago
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    thanks :)

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