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anonymous
 5 years ago
f energy(E), momentum(P) and force(F) are chosen as fundamental units. the dimension of mass in new system is.
A.E^1P^3
B.E^1P^2
E^2P^2
D.none of these.
anonymous
 5 years ago
f energy(E), momentum(P) and force(F) are chosen as fundamental units. the dimension of mass in new system is. A.E^1P^3 B.E^1P^2 E^2P^2 D.none of these.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You know : \[E_k = {{mv^2} \over 2}\] \[v = {p \over m}\] plug it in: \[E = {{m ({p \over m})^2} \over {2}} = {{p^2} \over {2m}} \rightarrow m = {p^2 \over 2E}\] the unit of 2 times E is still the same as the unit of E, thus (B) is the correct answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You do realise, that B lacks a factor of two, and more importantly both are the reciprocal of the correct expression that you derived.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ooops, my bad. Please use the eqution editor when posting :) questions.
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