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anonymous
 5 years ago
Graph the feasible region to the following system of inequalities
y2x≥1
2x+3y≥6
anonymous
 5 years ago
Graph the feasible region to the following system of inequalities y2x≥1 2x+3y≥6

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or how would you go about solving it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0draw the two lines, the feasible region lies above both of the lines

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0graph the lines: y2x = 1 and 2x +3y = 6

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then determine which point, not on the line; satisfies the equatons

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if the inequalities were less than or equal to would i shade below the lines?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pick (x=0,y=0) since its not on the line.... if it makes a true statement, sahde that side; if false? shaded the other side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0feasible region can be found by putting (0,0) in the line,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0origin is easiest point to check for the required region

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0by true statement i mean, use it in the original inequality :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0substituting x=0 and y=0 o greater than /equal 1,false

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the area opposite to origin is shaded

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0similar for the second line if the two region coincide, it is the required region, otherwise solution does not exist
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