Graph the feasible region to the following system of inequalities y-2x≥1 2x+3y≥6

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Graph the feasible region to the following system of inequalities y-2x≥1 2x+3y≥6

Mathematics
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with what?
or how would you go about solving it?
draw the two lines, the feasible region lies above both of the lines

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Other answers:

graph the lines: y-2x = 1 and 2x +3y = 6
then determine which point, not on the line; satisfies the equatons
if the inequalities were less than or equal to would i shade below the lines?
pick (x=0,y=0) since its not on the line.... if it makes a true statement, sahde that side; if false? shaded the other side
feasible region can be found by putting (0,0) in the line,
yes amistre is right
origin is easiest point to check for the required region
by true statement i mean, use it in the original inequality :)
\[y-2x \ge 1\]
substituting x=0 and y=0 o greater than /equal 1,false
so the area opposite to origin is shaded
similar for the second line if the two region coincide, it is the required region, otherwise solution does not exist

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