anonymous
  • anonymous
Graph the feasible region to the following system of inequalities y-2x≥1 2x+3y≥6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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amistre64
  • amistre64
with what?
anonymous
  • anonymous
or how would you go about solving it?
anonymous
  • anonymous
draw the two lines, the feasible region lies above both of the lines

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More answers

amistre64
  • amistre64
graph the lines: y-2x = 1 and 2x +3y = 6
amistre64
  • amistre64
then determine which point, not on the line; satisfies the equatons
anonymous
  • anonymous
if the inequalities were less than or equal to would i shade below the lines?
amistre64
  • amistre64
pick (x=0,y=0) since its not on the line.... if it makes a true statement, sahde that side; if false? shaded the other side
anonymous
  • anonymous
feasible region can be found by putting (0,0) in the line,
anonymous
  • anonymous
yes amistre is right
anonymous
  • anonymous
origin is easiest point to check for the required region
amistre64
  • amistre64
by true statement i mean, use it in the original inequality :)
anonymous
  • anonymous
\[y-2x \ge 1\]
anonymous
  • anonymous
substituting x=0 and y=0 o greater than /equal 1,false
anonymous
  • anonymous
so the area opposite to origin is shaded
anonymous
  • anonymous
similar for the second line if the two region coincide, it is the required region, otherwise solution does not exist

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