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by the simultaneous solution of both lines
i saw the 1,1 with the intersection but did not find the (2.25,0) and the (1/2,)
1/2,0 i mean
both the points lie on x-axis
mean they are the intersection of lines with x-axis
i got the 1,1 intersection using my calculator but the 1/2,0 and 2.25, 0 did not come up. how would i find those?
\[4x+5y \le 9\]
2x-y≥1 is this a typo?
\[2x-y \ge 1\]
thats what my teacher put
oh i have to write the equtions instead of inequalities
the answers are y ≤ 9-4x/5 and y ≤ 2x-1
4x+5y=9 y=0 gives x=9/4=2.25 point of intersection of the line and x-axis is (2.25,0)
likewise for the second eqn 2x-y=1 y=0 x=1/2 point is (1/2,0)
is the 5 in the deonominator a typo on his part?
5 in denominator?
this is how we get the corner points
on his answer key it says 9-4x/5
that makes more sense thanks a lot
so should i change the answer on the key where it says 9-4x/5?
is it y=9-4x/5?
it was originally 4x+5y≤ 9
to draw the line transform it into eqn 4x+5y=9
then he has his answer as y ≤ 9-4x/5
the x should then be move to the other side
which x?actually m not getting you what you actually want
u are to maximize the objective function subject to some constraints...right?
for that u r given two lines and first quadrant
we draw the lines n mark the feasible region, just like explained in ur previous post
maximum value liea at one of the corner points
ok that makes more sense
so r u fine with it now?