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anonymous

  • 5 years ago

maximize the objective function p = 3x+y sibject to the following constraints 4x+5y≤9 2x-y≥1 x≥0 y≥0 on my teachers answer sheet ht has 1/2,0 as his corner points 2.25,0 as another 1,1(which is the intersection of the two lines), how did my teacher get the other two corner points?

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  1. anonymous
    • 5 years ago
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    by the simultaneous solution of both lines

  2. anonymous
    • 5 years ago
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    i saw the 1,1 with the intersection but did not find the (2.25,0) and the (1/2,)

  3. anonymous
    • 5 years ago
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    1/2,0 i mean

  4. anonymous
    • 5 years ago
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    both the points lie on x-axis

  5. anonymous
    • 5 years ago
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    mean they are the intersection of lines with x-axis

  6. anonymous
    • 5 years ago
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    i got the 1,1 intersection using my calculator but the 1/2,0 and 2.25, 0 did not come up. how would i find those?

  7. anonymous
    • 5 years ago
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    \[4x+5y \le 9\]

  8. anonymous
    • 5 years ago
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    x=0

  9. anonymous
    • 5 years ago
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    y=0

  10. amistre64
    • 5 years ago
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    2x-y≥1 is this a typo?

  11. anonymous
    • 5 years ago
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    \[2x-y \ge 1\]

  12. anonymous
    • 5 years ago
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    thats what my teacher put

  13. anonymous
    • 5 years ago
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    oh i have to write the equtions instead of inequalities

  14. anonymous
    • 5 years ago
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    the answers are y ≤ 9-4x/5 and y ≤ 2x-1

  15. anonymous
    • 5 years ago
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    4x+5y=9 y=0 gives x=9/4=2.25 point of intersection of the line and x-axis is (2.25,0)

  16. anonymous
    • 5 years ago
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    likewise for the second eqn 2x-y=1 y=0 x=1/2 point is (1/2,0)

  17. anonymous
    • 5 years ago
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    is the 5 in the deonominator a typo on his part?

  18. anonymous
    • 5 years ago
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    5 in denominator?

  19. anonymous
    • 5 years ago
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    this is how we get the corner points

  20. anonymous
    • 5 years ago
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    on his answer key it says 9-4x/5

  21. anonymous
    • 5 years ago
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    that makes more sense thanks a lot

  22. anonymous
    • 5 years ago
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    so should i change the answer on the key where it says 9-4x/5?

  23. anonymous
    • 5 years ago
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    is it y=9-4x/5?

  24. anonymous
    • 5 years ago
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    it was originally 4x+5y≤ 9

  25. anonymous
    • 5 years ago
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    fine..what next?

  26. anonymous
    • 5 years ago
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    to draw the line transform it into eqn 4x+5y=9

  27. anonymous
    • 5 years ago
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    then he has his answer as y ≤ 9-4x/5

  28. anonymous
    • 5 years ago
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    oh ok

  29. anonymous
    • 5 years ago
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    correct

  30. anonymous
    • 5 years ago
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    what next?

  31. anonymous
    • 5 years ago
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    the x should then be move to the other side

  32. anonymous
    • 5 years ago
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    the 4x

  33. anonymous
    • 5 years ago
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    which x?actually m not getting you what you actually want

  34. anonymous
    • 5 years ago
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    u are to maximize the objective function subject to some constraints...right?

  35. anonymous
    • 5 years ago
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    thats correct

  36. anonymous
    • 5 years ago
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    for that u r given two lines and first quadrant

  37. anonymous
    • 5 years ago
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    we draw the lines n mark the feasible region, just like explained in ur previous post

  38. anonymous
    • 5 years ago
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    maximum value liea at one of the corner points

  39. anonymous
    • 5 years ago
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    lies*

  40. anonymous
    • 5 years ago
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    ok that makes more sense

  41. anonymous
    • 5 years ago
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    so r u fine with it now?

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spraguer (Moderator)
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