anonymous
  • anonymous
maximize the objective function p = 3x+y sibject to the following constraints 4x+5y≤9 2x-y≥1 x≥0 y≥0 on my teachers answer sheet ht has 1/2,0 as his corner points 2.25,0 as another 1,1(which is the intersection of the two lines), how did my teacher get the other two corner points?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
by the simultaneous solution of both lines
anonymous
  • anonymous
i saw the 1,1 with the intersection but did not find the (2.25,0) and the (1/2,)
anonymous
  • anonymous
1/2,0 i mean

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More answers

anonymous
  • anonymous
both the points lie on x-axis
anonymous
  • anonymous
mean they are the intersection of lines with x-axis
anonymous
  • anonymous
i got the 1,1 intersection using my calculator but the 1/2,0 and 2.25, 0 did not come up. how would i find those?
anonymous
  • anonymous
\[4x+5y \le 9\]
anonymous
  • anonymous
x=0
anonymous
  • anonymous
y=0
amistre64
  • amistre64
2x-y≥1 is this a typo?
anonymous
  • anonymous
\[2x-y \ge 1\]
anonymous
  • anonymous
thats what my teacher put
anonymous
  • anonymous
oh i have to write the equtions instead of inequalities
anonymous
  • anonymous
the answers are y ≤ 9-4x/5 and y ≤ 2x-1
anonymous
  • anonymous
4x+5y=9 y=0 gives x=9/4=2.25 point of intersection of the line and x-axis is (2.25,0)
anonymous
  • anonymous
likewise for the second eqn 2x-y=1 y=0 x=1/2 point is (1/2,0)
anonymous
  • anonymous
is the 5 in the deonominator a typo on his part?
anonymous
  • anonymous
5 in denominator?
anonymous
  • anonymous
this is how we get the corner points
anonymous
  • anonymous
on his answer key it says 9-4x/5
anonymous
  • anonymous
that makes more sense thanks a lot
anonymous
  • anonymous
so should i change the answer on the key where it says 9-4x/5?
anonymous
  • anonymous
is it y=9-4x/5?
anonymous
  • anonymous
it was originally 4x+5y≤ 9
anonymous
  • anonymous
fine..what next?
anonymous
  • anonymous
to draw the line transform it into eqn 4x+5y=9
anonymous
  • anonymous
then he has his answer as y ≤ 9-4x/5
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
correct
anonymous
  • anonymous
what next?
anonymous
  • anonymous
the x should then be move to the other side
anonymous
  • anonymous
the 4x
anonymous
  • anonymous
which x?actually m not getting you what you actually want
anonymous
  • anonymous
u are to maximize the objective function subject to some constraints...right?
anonymous
  • anonymous
thats correct
anonymous
  • anonymous
for that u r given two lines and first quadrant
anonymous
  • anonymous
we draw the lines n mark the feasible region, just like explained in ur previous post
anonymous
  • anonymous
maximum value liea at one of the corner points
anonymous
  • anonymous
lies*
anonymous
  • anonymous
ok that makes more sense
anonymous
  • anonymous
so r u fine with it now?

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