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by the simultaneous solution of both lines

i saw the 1,1 with the intersection but did not find the (2.25,0) and the (1/2,)

1/2,0 i mean

both the points lie on x-axis

mean they are the intersection of lines with x-axis

\[4x+5y \le 9\]

x=0

y=0

2x-y≥1 is this a typo?

\[2x-y \ge 1\]

thats what my teacher put

oh i have to write the equtions instead of inequalities

the answers are y ≤ 9-4x/5 and y ≤ 2x-1

4x+5y=9
y=0 gives
x=9/4=2.25
point of intersection of the line and x-axis is (2.25,0)

likewise for the second eqn
2x-y=1
y=0
x=1/2
point is (1/2,0)

is the 5 in the deonominator a typo on his part?

5 in denominator?

this is how we get the corner points

on his answer key it says 9-4x/5

that makes more sense thanks a lot

so should i change the answer on the key where it says 9-4x/5?

is it y=9-4x/5?

it was originally 4x+5y≤ 9

fine..what next?

to draw the line transform it into eqn
4x+5y=9

then he has his answer as y ≤ 9-4x/5

oh ok

correct

what next?

the x should then be move to the other side

the 4x

which x?actually m not getting you what you actually want

u are to maximize the objective function subject to some constraints...right?

thats correct

for that u r given two lines and first quadrant

we draw the lines n mark the feasible region, just like explained in ur previous post

maximum value liea at one of the corner points

lies*

ok that makes more sense

so r u fine with it now?