## anonymous 5 years ago The one-to-one functions g and h are defined as follows. g={(-6,3),(3,-8),(5,-9),(7,-6)} h(x)=3x-2 Find The Following: g^-1 (3) = h^-1 (x) = (h o h) ^-1 (1) =

1. anonymous

since $g(-6)=3$ you get $g^{-1}(3)=-6$

2. anonymous

second one solve $3x-2=y$ for x to get $x=\frac{y+2}{3}$

3. anonymous

then write $h^{-1}(x)=\frac{x+2}{3}$

4. anonymous

now you know that $h^{-1}(x) = \frac{x+2}{3}$ so $h^{-1}(1)=\frac{1+2}{3}=1$ and therefore $h^{-1}(h^{-1}(1))=h^{-1}(1)=1$