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are we assuming that the sea floor is flat?

yes

10sqrt(13) * 1000 then

the minimal distance between 2 points on a plane is a stright line

its a pythag problem that has no real world application lol

it seems to be asking; how much to build a pipeline along the legs of the triangle tho doesnt it

not to me but my reading comprehension might be off.

1 if by land; 2 if by sea..... yeah, they want the minimal cost compared to yada yada yada

we have to determine at what cost the land pipe and the sea pipe are qual

yeah, below being a pictorial term

25980.76 for a straight run to the oil rig

it is; but they want some variation of that;

30 miles down shore AND 20 miles out to sea from a refinery

i take that to mean east 30 and then 20 north, for example. but of course i could be wrong.

60000 if we build it at a right angle

52426.40 if we go with a 45 at 10 feet from the start

C(x) = s(1500) + l(1000)

how to relate s an l? by angle perhaps?

sin(t) = l
cos(t) = 30 - cos(t) = s

if this was speed; then the fastest speed would be?

30mph

along which route :)

i dont understand your question?

its a matter if finding the route by land and by sea that is the cheapest to build

30(1000) + 20(1500) = 60 000 ; so just building it up the 30 then 20 is bad

is sqrt supposed to mean log?

log means log
sqrt means square root

what are you sqrting 11 down?

ideally, when the land pipe cost matches the sea pipe cost we have the cheapest cost

when s(1500) = l(1000) we balance out and have the cheapest cost for total pipe

o i get it ......

yes

thank you soooooo very much for your help

can you get it from here?

yes i can thanks

thanks

\[C'(x)=\frac{1500x}{\sqrt{x^2+400}}-1000\]
set = 0 to find the critical point get
\[x=8\sqrt{5}\]

i got it lol

ok

good luck.

thx

welcome

lol