## anonymous 5 years ago Find the exponential function that satisfies the conditions: initial population: 500, doubling every 4.62 days.

1. anonymous

let $x=x(initial)* e ^{at}$ where x(initial)=500 to find a, $1000=500*e ^{a*4.62}$ $a={\ln (1000/500)}/4.62$ =$0.15 day ^{-1}$ so the equation is $x=x(initial)*e ^{.15t}$

2. anonymous

gracias!