anonymous
  • anonymous
Partial Differential Equation
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
its number 1
anonymous
  • anonymous
Alright, I'll take a look.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So, the easiest things to see is that anything with a square is non-linear. I'm not certain what they mean by "semi" and "quasi" linear, to be honest.
anonymous
  • anonymous
The orders are the highest derivative in each equation, although I need to find my book on inseparable equations to be sure whether it's with respect to a single variable only or not (I believe it is).
anonymous
  • anonymous
So gamma and delta are 3rd and 4th order linear, respectively.
anonymous
  • anonymous
alpha and beta are both second order, but I view them as both non-linear. But I caution on this one, I'm not familiar with quasi-linear classifications.
anonymous
  • anonymous
Alright, the second part is a lot easier than I was trying to make it. You find the discriminant of each equation. If its zero, it's parabolic. If it's positive, its hyperbolic, negative, it's elliptic.
anonymous
  • anonymous
I'm sure you're familiar with characteristic equations, so I'll skip that one.
anonymous
  • anonymous
The last problem is simply doing what you know to do, and using the initial/boundary conditions to solve the PDE. Solve the general form as much as possible, finding the general and particular solutions, then solve for the coefficients if needed.
anonymous
  • anonymous
Any problems with solving the PDE?
anonymous
  • anonymous
Well, I have to go. You seem to either be busily working or have stepped away. I hope I helped in some way. Good luck!

Looking for something else?

Not the answer you are looking for? Search for more explanations.