anonymous
  • anonymous
If you observed a car traveling at a constant rate around a circular track of 100 m diameter in 5 seconds, what is it's rate of motion in m/s? Then what would it be in miles/hour?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
A circle of diameter d=100m has a radius of d/2=50m As \[v=\omega R\] and \[\omega=2\pi f\] \[f=1/T\] The period of the motion is the time taken for one circuit: T=5s So. \[v=\omega R =2\pi fR= 2\pi R/T = (100\pi)/5 = 62.8ms ^{-1}\] which is 153 miles per hour. pretty fast.
anonymous
  • anonymous
Thank-you, but I have one question. How come you didn't multiply the '2'? This is very helpful, and I am getting the same answer, but I am confused as to why the 2 isn't multiplied.
anonymous
  • anonymous
The radius which is 100/2=50 but it is then multiplied by 2 again so goes back to 100. so 2R=100. does that help?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yes, thank-you very much. You've been very helpful.

Looking for something else?

Not the answer you are looking for? Search for more explanations.