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K-1 is supposed to be low like a exponent but at bottom idk what its called?

index
A2=2*4-3=5
A3=2*5-3=7
A4=2*7-3=11
A5=2*11-3=18
and so on

whats the star mean?

multiply *

nevermind

thank you

might need to adjust for A1; tho, so lets check....
well, it dont match but i was close with it

is there a way I can write it with out typing so i can show you exactly how it looks

A1 = 4
A2= 2(4) - 3 = 5
A3= 2(5) - 3 = 7
A4= 2(7) - 3 = 11 is correct tho

write it without typing it.... prolly not

okay hold on ill use paint and up
load it

or like this maybe you'll understand
A = 2A -3
k (k-1)

do you understand now?

\[a _{k}\]

yesss :)

the solution is what I wrote, I cannot understand what amistre wrote :)

thank you do you have time for another

sure

Use mathematical induction 7+ 14+ 21+ 21 +28 +.....7N= 7N(N+1)/ 2

ok, do you now what induction is in maths?

7n(N+1) is all divided by 2 and not really

I know how to prove P(1) true but (k+1) is where im lost

and we are very happy now :)

thank you

I have more sorry its confusing to me

no prob

I figured its a geometric sequence

yep it is

so how do I solve?

I dont understand the problem completely

after that its (3/4)
what does this mean?

so the common ratio is 3/4 400, 300... and so on

so 3/4 of 300 then the next and next.. but I need to find out how many times it bounces til it stops

It will never stop than

well until it hits the ground?

oh I am stupid, I think it asks for the use of this formula:
a/(1-r)

here a=400 1-r=1/4
so the result is 1600

ohhh i seee :)