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anonymous
 5 years ago
Sequence Ak= 2a (k1)  3 if a1 =4 whats next 3 terms
anonymous
 5 years ago
Sequence Ak= 2a (k1)  3 if a1 =4 whats next 3 terms

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0K1 is supposed to be low like a exponent but at bottom idk what its called?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0index A2=2*43=5 A3=2*53=7 A4=2*73=11 A5=2*113=18 and so on

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1An = 2(An1) 3 An = 2^2 (An2)  2(3)  3 An = 2^3 (An3)  2^2(3)  2(3)  3 An = 2^n(A0)  3[x] x = 1 + 2 + 2^2 + 2^3 + ... + 2^n1 2x = 2 + 2^2 + 2^3 + ... + 2^n1 + 2^n 2x  x = 2^n  1 x = (2^n 1)/2 An = 2^n(A0)  3[(2^n 1)/2] perhaps?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1might need to adjust for A1; tho, so lets check.... well, it dont match but i was close with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is there a way I can write it with out typing so i can show you exactly how it looks

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1A1 = 4 A2= 2(4)  3 = 5 A3= 2(5)  3 = 7 A4= 2(7)  3 = 11 is correct tho

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1write it without typing it.... prolly not

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay hold on ill use paint and up load it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or like this maybe you'll understand A = 2A 3 k (k1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the k supposed to be up closer next to the a but set a little lower same for (k1) Like when you do a LOG

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you understand now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the solution is what I wrote, I cannot understand what amistre wrote :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you do you have time for another

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use mathematical induction 7+ 14+ 21+ 21 +28 +.....7N= 7N(N+1)/ 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, do you now what induction is in maths?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.07n(N+1) is all divided by 2 and not really

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know how to prove P(1) true but (k+1) is where im lost

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0induction is a technique to prove things has 3 steps 1. what you wrote: prove that it is true for N=1 2. Assume that it is true for any N 3. Prove that it is true for N+1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01. N=1 7=7*1(1+1)/2=7 we are happy :) 2. (called inductive step) Suppose this is true: 7+ 14+ 21+ 21 +28 +.....7N= 7N(N+1)/ 2 3. prove it for N+1 (we can use the inductive step) 7+ 14+ 21+ 21 +28 +.....7N+7(N+1)= this bit is 7+ 14+ 21+ 21 +28 +.....7N=7N(N+1)/ 2 so the whole is 7N(N+1)/ 2 +7(N+1)= 7(N+1)(N/2+1)=7(N+1)(N+2)/2 This completes the proof. (can you see why?)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and we are very happy now :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have more sorry its confusing to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A ball bounces 400 ft every second after that its (3/4) how many times does it bounce til it completely stops

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I figured its a geometric sequence

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dont understand the problem completely

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0after that its (3/4) what does this mean?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the common ratio is 3/4 400, 300... and so on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 3/4 of 300 then the next and next.. but I need to find out how many times it bounces til it stops

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It will never stop than

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a number multiplied by 3/4 a lot of times will be a small number but will never reach 0 in maths we say it is tending to 0 as we tend to infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well until it hits the ground?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh I am stupid, I think it asks for the use of this formula: a/(1r)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here a=400 1r=1/4 so the result is 1600
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