anonymous
  • anonymous
Sequence Ak= 2a (k-1) - 3 if a1 =4 whats next 3 terms
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
K-1 is supposed to be low like a exponent but at bottom idk what its called?
anonymous
  • anonymous
index A2=2*4-3=5 A3=2*5-3=7 A4=2*7-3=11 A5=2*11-3=18 and so on
anonymous
  • anonymous
whats the star mean?

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anonymous
  • anonymous
multiply *
anonymous
  • anonymous
nevermind
anonymous
  • anonymous
thank you
amistre64
  • amistre64
An = 2(An-1) -3 An = 2^2 (An-2) - 2(3) - 3 An = 2^3 (An-3) - 2^2(3) - 2(3) - 3 An = 2^n(A0) - 3[x] x = 1 + 2 + 2^2 + 2^3 + ... + 2^n-1 2x = 2 + 2^2 + 2^3 + ... + 2^n-1 + 2^n 2x - x = 2^n - 1 x = (2^n -1)/2 An = 2^n(A0) - 3[(2^n -1)/2] perhaps?
amistre64
  • amistre64
might need to adjust for A1; tho, so lets check.... well, it dont match but i was close with it
anonymous
  • anonymous
is there a way I can write it with out typing so i can show you exactly how it looks
amistre64
  • amistre64
A1 = 4 A2= 2(4) - 3 = 5 A3= 2(5) - 3 = 7 A4= 2(7) - 3 = 11 is correct tho
amistre64
  • amistre64
write it without typing it.... prolly not
anonymous
  • anonymous
okay hold on ill use paint and up load it
anonymous
  • anonymous
or like this maybe you'll understand A = 2A -3 k (k-1)
anonymous
  • anonymous
but the k supposed to be up closer next to the a but set a little lower same for (k-1) Like when you do a LOG
anonymous
  • anonymous
do you understand now?
anonymous
  • anonymous
\[a _{k}\]
anonymous
  • anonymous
yesss :)
anonymous
  • anonymous
the solution is what I wrote, I cannot understand what amistre wrote :)
anonymous
  • anonymous
thank you do you have time for another
anonymous
  • anonymous
sure
anonymous
  • anonymous
Use mathematical induction 7+ 14+ 21+ 21 +28 +.....7N= 7N(N+1)/ 2
anonymous
  • anonymous
ok, do you now what induction is in maths?
anonymous
  • anonymous
7n(N+1) is all divided by 2 and not really
anonymous
  • anonymous
I know how to prove P(1) true but (k+1) is where im lost
anonymous
  • anonymous
induction is a technique to prove things has 3 steps 1. what you wrote: prove that it is true for N=1 2. Assume that it is true for any N 3. Prove that it is true for N+1
anonymous
  • anonymous
1. N=1 7=7*1(1+1)/2=7 we are happy :) 2. (called inductive step) Suppose this is true: 7+ 14+ 21+ 21 +28 +.....7N= 7N(N+1)/ 2 3. prove it for N+1 (we can use the inductive step) 7+ 14+ 21+ 21 +28 +.....7N+7(N+1)= this bit is 7+ 14+ 21+ 21 +28 +.....7N=7N(N+1)/ 2 so the whole is 7N(N+1)/ 2 +7(N+1)= 7(N+1)(N/2+1)=7(N+1)(N+2)/2 This completes the proof. (can you see why?)
anonymous
  • anonymous
and we are very happy now :)
anonymous
  • anonymous
thank you
anonymous
  • anonymous
I have more sorry its confusing to me
anonymous
  • anonymous
A ball bounces 400 ft every second after that its (3/4) how many times does it bounce til it completely stops
anonymous
  • anonymous
no prob
anonymous
  • anonymous
I figured its a geometric sequence
anonymous
  • anonymous
yep it is
anonymous
  • anonymous
so how do I solve?
anonymous
  • anonymous
I dont understand the problem completely
anonymous
  • anonymous
after that its (3/4) what does this mean?
anonymous
  • anonymous
so the common ratio is 3/4 400, 300... and so on
anonymous
  • anonymous
so 3/4 of 300 then the next and next.. but I need to find out how many times it bounces til it stops
anonymous
  • anonymous
It will never stop than
anonymous
  • anonymous
a number multiplied by 3/4 a lot of times will be a small number but will never reach 0 in maths we say it is tending to 0 as we tend to infinity
anonymous
  • anonymous
well until it hits the ground?
anonymous
  • anonymous
oh I am stupid, I think it asks for the use of this formula: a/(1-r)
anonymous
  • anonymous
here a=400 1-r=1/4 so the result is 1600
anonymous
  • anonymous
ohhh i seee :)

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