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anonymous

  • 5 years ago

how do i solve x^3-4x^2+5x=50

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  1. amistre64
    • 5 years ago
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    x^3 -4x^2 +5x -50 = 0 can either try to factor by grouping or to trail and error it

  2. amistre64
    • 5 years ago
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    i aint got an eye for grouping :)

  3. amistre64
    • 5 years ago
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    1,50; 2,25; 5,10 seem to be it lets try 10 10 | 1 -4 5 50 0 10 60 ------------ 1 6 65 ..........aint gonna happen with that

  4. amistre64
    • 5 years ago
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    2? 2 | 1 -4 5 50 0 2 -4 ------------ 1 -2 1 ........ nope the quicekr way is to use a graphing program

  5. amistre64
    • 5 years ago
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    try 5 ? 5 | 1 -4 5 -50 0 5 5 50 ----------- 1 1 10 0 x = 5 is a root now to determine if the rest is factorable... x^2 +x +10 1 -40 = irreducible (x-5)(x^2 +x +10) is the factored form and the only root is x=5

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