anonymous
  • anonymous
when integrating radt times lnt by parts should u be lnt or rad t?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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amistre64
  • amistre64
thats a little tooooo cryptic, can you english it up some?
amistre64
  • amistre64
sqrt(t).ln(t) perhaps?
watchmath
  • watchmath
\(u=\ln t\)

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amistre64
  • amistre64
LN(t) looks alot like int
anonymous
  • anonymous
\[\int\limits_{1}^{\sqrt{5}}\sqrt{t}lnt\]dt
watchmath
  • watchmath
Here is a trick that most of the time worsk. Use I L A T E for choosing u. I(inverse), L(og), A(lgebraic), T(rig), E(xp). In your problem you have A(lgebraic) and L(og). Since L come first before A. Choose L as your u. To learn more look at here: http://www.youtube.com/watch?v=cdLF-_gymRI
anonymous
  • anonymous
ok thanks...so lets say dv=lntdt. what is v then? the antiderivative of lnt i mean?
watchmath
  • watchmath
Well \(\sqrt{t}\) is algebraic. So we choose L which is \(u=\ln t\) and \(dv=\sqrt{t}dt\)
anonymous
  • anonymous
tlnt-t is the integral of lnt. To find that, you need to use by parts

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