The line 3x-2y=12 has a) a slope of 3/2 and a y intercept of -6 b) a slope of -3/2 and a y intercept of 6 c) a slope of 3 and a y intercept of -2 d) a slope of -3 and a y intercept of -6

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The line 3x-2y=12 has a) a slope of 3/2 and a y intercept of -6 b) a slope of -3/2 and a y intercept of 6 c) a slope of 3 and a y intercept of -2 d) a slope of -3 and a y intercept of -6

Mathematics
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i think the answer is either a or b!
why dont you try rearranging your equation such that you get it in the form y = mx + b
ok lets see.....first you have to add -2y on both sides?

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Other answers:

no, you are trying to remove -2y from the left hand side. so you add +2y to both sides so that your LHS becomes 3x-2y+2y -----> 3x+0
2y=3x-12 then divide them with 2 y=3/2 x -6 a
y=mx+c c = y intercept m = slope y=3/2 x -6 y = m x + c clear? m=3/2 , c =-6

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