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anonymous
 5 years ago
is anyone good with rational exponents??
anonymous
 5 years ago
is anyone good with rational exponents??

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahh can you help me with this equation: 3^1/3*9^1/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factor out the 1/3 because they are the same exponent so you have (3*9)^1/3 which is like the cube root of 27 which is 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think the answer is 3sq rt of 3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0THANK YOU dancr_on_fire!! :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem... i always find it easier to think of factional exponents like roots

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(3.3.3)^1/3 = 3, good job dancr

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how would i simplify 8^4/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cube root of 8 is 2, 2^4 = 16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay awesome!! what about...(8a^6)^2/3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with this you multiply your exponents first

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply the exponents first: \[(8a^{6})^{\frac{2}{3}}=8^{\frac{2}{3}}a^4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0satellite73 you are the best! are you good with finding LCM?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in english \[8^{\frac{2}{3}}\] means the reciprocal of the cube root of 8 squared. the cube root of 8 is 2. 2 squared is 4. and the reciprocal of 4 is \[\frac{1}{4}\] so answer is \[\frac{a^4}{4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, 400x^24y^2, 20x^2+2^yx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you really mean lcm? because these are sums and difference. ok factor each one. \[400x^24y^2=4(100x^2y^2)\]which is the difference of two squares. \[=4(10xy)(10x+y)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[20x^2+2y^2=2x(10x+y)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for your least common multiple you need all the factors you see, not repeated!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the factors are \[4\] \[x\] \[10xy\] \[10x+y\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okayyy i see! that makes sense!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply together to get \[4x(10x+y)(10xy)\] hope it is clear. same way to find lcm of two numbers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me with writing this next one in radical form? 6x^3/2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes that makes way better sense now!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x^{\frac{m}{n}}=\sqrt[n]{x^m}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for a fractional exponent, numerator is the power, denominator is the root.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[6x^{\frac{3}{2}}=6\sqrt{x^3}\]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0check out the paper i sent should make it clear.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay lemme check it out! thank you!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you always online? cause you are the biggest help! hopefully you can help me again soon!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am often here these days practicing my latex. if you want you can email me at satellite73.openstudy@gmail.com

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0perfect! i am trying to finish an online math class by tomorrow in order to be able to graduate...i have about 70% more to complete! so youre a big help!
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