is anyone good with rational exponents??

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- anonymous

is anyone good with rational exponents??

- chestercat

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- toxicsugar22

yes

- amistre64

maybe

- anonymous

ahh can you help me with this equation: 3^1/3*9^1/3

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## More answers

- anonymous

probably

- anonymous

factor out the 1/3 because they are the same exponent so you have (3*9)^1/3 which is like the cube root of 27 which is 3

- anonymous

i think the answer is 3sq rt of 3?

- toxicsugar22

i dont know tht

- anonymous

THANK YOU dancr_on_fire!! :)

- anonymous

no problem... i always find it easier to think of factional exponents like roots

- amistre64

(3.3.3)^1/3 = 3, good job dancr

- anonymous

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- anonymous

how would i simplify 8^4/3

- anonymous

cube root of 8 is 2, 2^4 = 16

- anonymous

okay awesome!! what about...(8a^-6)^-2/3

- anonymous

with this you multiply your exponents first

- anonymous

multiply the exponents first:
\[(8a^{-6})^{-\frac{2}{3}}=8^{-\frac{2}{3}}a^4\]

- anonymous

satellite73 you are the best! are you good with finding LCM?

- anonymous

of polynomials

- anonymous

in english \[8^{-\frac{2}{3}}\] means the reciprocal of the cube root of 8 squared. the cube root of 8 is 2. 2 squared is 4. and the reciprocal of 4 is \[\frac{1}{4}\] so answer is \[\frac{a^4}{4}\]

- anonymous

example?

- anonymous

okay, 400x^2-4y^2, 20x^2+2^yx

- anonymous

do you really mean lcm? because these are sums and difference. ok factor each one.
\[400x^2-4y^2=4(100x^2-y^2)\]which is the difference of two squares.
\[=4(10x-y)(10x+y)\]

- anonymous

\[20x^2+2y^2=2x(10x+y)\]

- anonymous

so for your least common multiple you need all the factors you see, not repeated!

- anonymous

the factors are \[4\]
\[x\]
\[10x-y\]
\[10x+y\]

- anonymous

okayyy i see! that makes sense!

- anonymous

multiply together to get
\[4x(10x+y)(10x-y)\]
hope it is clear. same way to find lcm of two numbers.

- anonymous

can you help me with writing this next one in radical form? 6x^3/2

- anonymous

yes that makes way better sense now!

- anonymous

\[x^{\frac{m}{n}}=\sqrt[n]{x^m}\]

- anonymous

for a fractional exponent, numerator is the power, denominator is the root.

- anonymous

\[6x^{\frac{3}{2}}=6\sqrt{x^3}\]\]

- anonymous

check out the paper i sent should make it clear.

- anonymous

okay lemme check it out! thank you!

- anonymous

are you always online? cause you are the biggest help! hopefully you can help me again soon!

- anonymous

i am often here these days practicing my latex. if you want you can email me at satellite73.openstudy@gmail.com

- anonymous

perfect! i am trying to finish an online math class by tomorrow in order to be able to graduate...i have about 70% more to complete! so youre a big help!

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