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anonymous
 5 years ago
is anyone good with trigometry??
anonymous
 5 years ago
is anyone good with trigometry??

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0euclid maybe; but hes dead :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can use the pythagorean theorem to find b and then use that to find a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this triangle is not possible... your hypotenuse will always be longer than each leg... this is not the case in this picture

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b^2 + 13^2 = (12+a)^2 5^2 + a^2 = b^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about this? How long is a string reaching from the top of a 8ft pole to a point 5 ft from the base of the pole?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(12+a)^2  13^2 = 5^2 + a^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0looks like similar triangles to me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm trying to study for finals...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0144 + a^2 + 24a  196 = 25 + a^2 144  196  25 = 24a 144  196  25 = a  24

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre64 which one is that for?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a = 77/24..... the first one you posted

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how about... A slide 4.1 m long makes an angle of 28 degrees with the ground. How high is the top of the slide above the ground?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats all you do for that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes; unless you wanna put it into a calculator to get an approx distance

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, that first triangle set up could have been ration

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what about find the missing abgle and side measure of triangle ABC, given that angle A=50 degrees, Angle C= 90 degrees, and CB=7

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0PEOPLE! it is much easier to solve with similar triangles! 5/13 = a/5  > a = 25/13

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0dhat; yeah, i know :) just thought id give it a shot the other way lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0given 2 degrees and a side you can do law of cosines to get another side and then law of sine it with some careful planning

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0given angles and a side; law of sines might be the best optio

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how excatly would i do that.?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0never mind that; this is a 90 degree to begin with ABC, given that angle A=50 degrees, Angle C= 90 degrees, and CB=7

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.07 AC  =  tho sin 50 sin(40)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.07 ab  =  = abt 9.12 sin 50 sin90

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my two options are; A) <B=40 degrees, C=9.1, b=5.9 B) <B=40 degrees, C=8.6, b=5.9

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the trick is to dbl check that and see how close it is :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so how'd you get the 7 over sin 50 and the ab over sin90?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats the law of sines; side a side b side c  =  =  sin(a) sin(b) sin(c)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.07  is a given; so the others just fall from that sin(50)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh okay. My teacher sucked at teaching the law of sines so i can never get it.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0cos(g) = a/sqrt(45) sin^2 + cos ^2 = 1 sin^2 + a^2/45 = 1 sin^2 = 1  a^2/45 sin = sqrt(1a^2/45) tan(g) = sqrt(1(a^2/45))  a^2/sqrt(45)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tan(g) = sqrt(1(a^2/45)) (sqrt(45))  a^2 tan(g) = sqrt(1(a^2/45)(45))  a^2 tan(g) = sqrt(45a^2)  a^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How about this.? Thank you for all your help too. If you need anything in return I'd be glad to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x = 23 sqrt(2) y = 23 + 46cos 30

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey you wrote this: tan(g) = sqrt(45a^2)  a^2 But how would i finish it.?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0With regard to 20110518.13.41.36.jpg: \[a=5 \text{Cos}\left[\frac{\pi }{2}\text{ArcTan}\left[\frac{5}{12}\right]\right]=\frac{25}{13} \]\[b=5 \text{Sin}\left[\frac{\pi }{2}\text{ArcTan}\left[\frac{5}{12}\right]\right]=\frac{60}{13} \]\[\sqrt{\left(\frac{25}{13}\right)^2+\left(\frac{60}{13}\right)^2}=5 \]
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