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anonymous
 5 years ago
How would a person graph
y=1/2(x+4)^25 and find the foci and focus?
anonymous
 5 years ago
How would a person graph y=1/2(x+4)^25 and find the foci and focus?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No foci http://www.wolframalpha.com/input/?i=focus+y%3D1%2F2%28x%2B4%29^25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right but how does a person get 4, 0/2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on the websouce is it given as a result

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay the standard equation is given by \[(xh)^2=4p(yk)\] lets convert your equation into the standard form \[y=\frac{1}{2}(x+4)^25\Rightarrow (y+5) = \frac{1}{2}(x+4)^2\Rightarrow 2(y+5)=(x+4)^2\] Now we have the equations looking alike \[(xh)^2=4p(yk)\] \[(x+4)^2=2(y+5)\] \[h=4 \rightarrow h=4 \text{ and 4p = 2 so p = }\frac{1}{2}\text{ and k=5 so k = 5}\] \[\text{The focus is given by (h,k+p)}\Rightarrow \text{(4, 5+}\frac{1}{2}\text{)}\Rightarrow (4, \frac{9}{2})\] hope that helps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0p is the directrix, directrix is line that runs perpendicular to axis of symmetry of parabola distance to focus equals distance to directrix < definition of parabola
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