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its a vector related problem
add the vector to get the red travel distance vector
<20,0> is the westward vector ; and <0,-15> is the southward vector
the new vector is simply: <20,0> <0,-15> -------- <20,-15>
the direction traveled is the tan^-1 (y/x) + pi
-15/20 = -3/4 tan^-1(-3/4) =abt 233.13 degrees if i did it right
had to add 270 to it to get itin the proper qudrant
and the distance traveled is just the pythag of the y and x components
any of this make sense?
No...I wish though.
hmm.... a vector is just an arrow that points in any direction and indicates the distance traveled; they can be called directed line segments
when we add them, they form a new arrow that measures a new direction and length
you essentially have the ferry being thrown off course by the river; by 15 meters every sec right?
well; 15 miles for every hour travled
if we pythag the new direction; we get 20 west; and 15 south; those are the legs of a triangle and the distance actually covered in one hour is the hypotenuse of that triangle
sqrt(20^2 + 15^2) = distance traveled in one hour
in this case; its moved 25 miles in one hour...... or 25 mph
the direction it moved is to the south and west...measured from some starting point; usually idicated as due est
due east is the inital starting point of angle measures...
any of this ringing bells yet :)
I understand better now, thank you for helping me so much :)