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anonymous

  • 5 years ago

A footbridge is in the shape of an arc of a circle. The bridge is 6 ft tall and 25 ft wide. What is the radius of the circle that contains the bridge?

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  1. anonymous
    • 5 years ago
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    wouldnt it be half of 25?

  2. anonymous
    • 5 years ago
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    maybe, but then whats the 6 for?

  3. anonymous
    • 5 years ago
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    thats what i couldnt figure out

  4. anonymous
    • 5 years ago
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    haha it's confusing.

  5. anonymous
    • 5 years ago
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    i'll keep trying ha

  6. anonymous
    • 5 years ago
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    i really dont know though sorry!

  7. amistre64
    • 5 years ago
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    i do :)

  8. anonymous
    • 5 years ago
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    it okaye michelle(: haha and can you help then.? :P

  9. amistre64
    • 5 years ago
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    w^2 ----- + rise/2 its how i made a thousand arches rise/8

  10. amistre64
    • 5 years ago
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    25^2/6 = n n/8 = m m+ 6/2 = radius

  11. amistre64
    • 5 years ago
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    abt 16.02

  12. amistre64
    • 5 years ago
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    we would have walkthrus that the prints needed arches so high by so wide; i figured id find a formula for determing how far to put my pivot point to attc my chalkline or tape to so I could make the required arch

  13. amistre64
    • 5 years ago
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    width^2 ------ + rise/2 = radius of circle rise/8

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