anonymous
  • anonymous
A footbridge is in the shape of an arc of a circle. The bridge is 6 ft tall and 25 ft wide. What is the radius of the circle that contains the bridge?
Mathematics
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anonymous
  • anonymous
A footbridge is in the shape of an arc of a circle. The bridge is 6 ft tall and 25 ft wide. What is the radius of the circle that contains the bridge?
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
wouldnt it be half of 25?
anonymous
  • anonymous
maybe, but then whats the 6 for?
anonymous
  • anonymous
thats what i couldnt figure out

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anonymous
  • anonymous
haha it's confusing.
anonymous
  • anonymous
i'll keep trying ha
anonymous
  • anonymous
i really dont know though sorry!
amistre64
  • amistre64
i do :)
anonymous
  • anonymous
it okaye michelle(: haha and can you help then.? :P
amistre64
  • amistre64
w^2 ----- + rise/2 its how i made a thousand arches rise/8
amistre64
  • amistre64
25^2/6 = n n/8 = m m+ 6/2 = radius
amistre64
  • amistre64
abt 16.02
amistre64
  • amistre64
we would have walkthrus that the prints needed arches so high by so wide; i figured id find a formula for determing how far to put my pivot point to attc my chalkline or tape to so I could make the required arch
amistre64
  • amistre64
width^2 ------ + rise/2 = radius of circle rise/8

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