Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

myininaya Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{7}{20}f+\frac{2}{5}=\frac{1}{4}f\] get your f's together add 7f/20 on both sides \[\frac{2}{5}=\frac{1}{4}f+\frac{7}{20}f\] find a common denominator \[\frac{2}{5}=\frac{5}{20}f+\frac{7}{20}f\] \[\frac{2}{5}=\frac{12}{20}f\] we can simplify 12/12 \[\frac{2}{5}=\frac{3}{5}f\] \[\frac{5}{3}*\frac{2}{5}=f\]
 3 years ago

A7med Group TitleBest ResponseYou've already chosen the best response.0
2/5=1/4f+7/20f 2/5=5/20f+7/20f 2/5=12/20f 4f=60 f=15
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
i get f=2/3 lets check
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
a7med did you do f=20/12*2/5
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
so you tried to cross multipliy so it should be 5*12f=2*20
 3 years ago

lillywazhere Group TitleBest ResponseYou've already chosen the best response.0
thank u
 3 years ago

A7med Group TitleBest ResponseYou've already chosen the best response.0
no, u 20f*2=5*12 i'm sure
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
we have 12f/20=2/5 to get f by itself we multiplied by the reciprocal of 12/20 on both sides giving us (20/12)(12f/20)=(20/12)(2/5) f=40/60=2/3
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
we can also check f=2/3 so we plug 2/3 whereever we see an f in the orignal problem (7/20)(2/3)+2/5=(1/4)(2/3) 14/60+2/5=2/12 7/30+2/5=2/12 7/30+12/30=2/12 5/30=2/12 1/6=1/6 2/3 is definitely correct!
 3 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.