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aloramichelle

  • 4 years ago

Find the logarithm. log_4(1/64)=?

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  1. daniel987600
    • 4 years ago
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    1/3

  2. cbarrick
    • 4 years ago
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    let \(y=log_4(1/64)\) Then you can do \(4^y=1/64\) \(1/64=64^{-1}\) and \(64=4^3\) so \(1/64=4^{-3}\) \[4^y=4^{-3}\] so \(y=-3\)

  3. A7med
    • 4 years ago
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    -3

  4. dinabina78
    • 4 years ago
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    Daniel I have another for you to look at please... :)

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