anonymous
  • anonymous
solve equation by taking square roots: k^2+76 how do i do that?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
This is not an equation. In equations, there must be an equality sign.
anonymous
  • anonymous
the plus was supposed to be =, sorrry. k^2=76
anonymous
  • anonymous
if the plus sign was an equals sign: the square root of k^2 is k. so k= sqrt of 76. which is 8.717797887....

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anonymous
  • anonymous
But if you're asking about \(k^2+76=0\) then it has no real solution.
anonymous
  • anonymous
OK then, NK got the answer for you :D.
anonymous
  • anonymous
\[k^2=76 \implies k=-\sqrt{76}, k=\sqrt{76}\]
anonymous
  • anonymous
So two solutions.
anonymous
  • anonymous
so how would you get the answer for k^2=16? ...
anonymous
  • anonymous
K can have two values; \(k=4\) or \(k=-4\)
anonymous
  • anonymous
do you just find the square root of the last number?
anonymous
  • anonymous
Yep, and take both positive and negative values.
anonymous
  • anonymous
so x2=21 is 4.58.... or no? :(
anonymous
  • anonymous
Exactly \(x=4.58\) or \(x=-4.58\) :)

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