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anonymous

  • 5 years ago

solve equation by taking square roots: k^2+76 how do i do that?

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  1. anonymous
    • 5 years ago
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    This is not an equation. In equations, there must be an equality sign.

  2. anonymous
    • 5 years ago
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    the plus was supposed to be =, sorrry. k^2=76

  3. anonymous
    • 5 years ago
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    if the plus sign was an equals sign: the square root of k^2 is k. so k= sqrt of 76. which is 8.717797887....

  4. anonymous
    • 5 years ago
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    But if you're asking about \(k^2+76=0\) then it has no real solution.

  5. anonymous
    • 5 years ago
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    OK then, NK got the answer for you :D.

  6. anonymous
    • 5 years ago
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    \[k^2=76 \implies k=-\sqrt{76}, k=\sqrt{76}\]

  7. anonymous
    • 5 years ago
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    So two solutions.

  8. anonymous
    • 5 years ago
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    so how would you get the answer for k^2=16? ...

  9. anonymous
    • 5 years ago
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    K can have two values; \(k=4\) or \(k=-4\)

  10. anonymous
    • 5 years ago
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    do you just find the square root of the last number?

  11. anonymous
    • 5 years ago
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    Yep, and take both positive and negative values.

  12. anonymous
    • 5 years ago
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    so x2=21 is 4.58.... or no? :(

  13. anonymous
    • 5 years ago
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    Exactly \(x=4.58\) or \(x=-4.58\) :)

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