solve this differential equation!?! (x^2 + a^2)y' = xy please help..

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solve this differential equation!?! (x^2 + a^2)y' = xy please help..

Mathematics
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dy/y = x/(x^2+a^2) dx integral each side...
\(\int\frac{dy}{y}=\int\frac{x\,dx}{a^2+x^2}\) \(\ln|y|=\frac{1}{2}\ln(a^2+x^2)+C\)
oo ok..and we just solve for y?

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Other answers:

use e
\(|y|=Ae^{\ln(\sqrt{a^2+x^2})}=A\sqrt{a^2+x^2}\) \(y=\pm A\sqrt{a^2+x^2}=A\sqrt{a^2+x^2}\)
what is the capital A??
That is to replace \(e^C\) which is just another constant.
oo for e^(1/2)..?
no for e^c
\(\frac{1}{2}\ln (a^2+x^2)=\ln(a^2+x^2)^{1/2}\) by the property of \(\ln\).
yes..i understand it now thanks guys!
I think we need to add small detail that \(A >0\).

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