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anonymous

  • 5 years ago

Give the center radius of each equation.Then sketch the graph. (x-3)square + (y+4)square minus 9=0

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  1. anonymous
    • 5 years ago
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    \[(x-3)^2+(y+4)^2=9\] if center = (h,k) and radius = r, then the general form is \[(x-h)^2+(y-k)^2=r^2\] Thus center=(3,-4) and r=3

  2. anonymous
    • 5 years ago
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    why is 4 negative and 3 positive and thank so much

  3. anonymous
    • 5 years ago
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    because it must be in the form (x-h)^2 and so for (x-h) to equal (x-3), h must be positive 3. Similarly, if (y+4)=(y-k), then k=-4

  4. anonymous
    • 5 years ago
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    ok how is this supose to be graphed because im looking at the example of the graph and it very difficult

  5. anonymous
    • 5 years ago
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    do you have a compass?

  6. anonymous
    • 5 years ago
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    no

  7. anonymous
    • 5 years ago
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    well, it's going to be a circle, so I would, starting from (3,-4), go 3 units up, down, left and right.

  8. anonymous
    • 5 years ago
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    then draw a curve through those four points by hand and make it as circular as you can?

  9. anonymous
    • 5 years ago
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    ok one more question same problem different equation

  10. anonymous
    • 5 years ago
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    x square + y square = 36

  11. anonymous
    • 5 years ago
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    ok, this one is actually a little simpler. See, to get it in the standard form, all we do is rewrite it as \[(x-0)^2+(y-0)^2=6^2\] now clearly it's the same equation as the one you gave me, just a little more convenient

  12. anonymous
    • 5 years ago
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    and from this we determine the center is (0,0) and the radius is 6

  13. anonymous
    • 5 years ago
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    why is it 6 when you square root it

  14. anonymous
    • 5 years ago
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    sorry dumb question

  15. anonymous
    • 5 years ago
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    i see lol

  16. anonymous
    • 5 years ago
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    that's alright, as long as you understand it now

  17. anonymous
    • 5 years ago
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    and if you don't, i'd be happy to answer anything else

  18. anonymous
    • 5 years ago
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    man you have been a big help ill be sure to be back on this mabey in a hour or so or minutes thanks :)

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