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  • 5 years ago

A car, weighing m kg, and a truck, weighing 4m kg, collide at an angle of A . Initially they are traveling at the same velocity. After the collision they move off together at an angle of B conserving momentum (moves off together). a) Show that tan() = 4 sin A divided by 4 cos A + 1 . b) Show that if their initial velocity is u the velocity that they move off at is v = u/5 sqrt (17 + 8 cos ). c) Find the velocity and direction they move off at if A= pi/2 2 What value of A gives the minimum velocity?

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  1. anonymous
    • 5 years ago
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    a)from the conservation of LINEAR momentum- \[m*\cos o +4m*\cos A =(m+4m)\cos B=5mcos B\] \[msin 0+4msin A= 5\sin B\] [above two are get by resolving the momentum into horizontal & perpendicular components ] so,\[\tan B= (5\sin B)/(5\cos B)\] \[=4msin A/(m+4mcos A)\] \[=4\sin A /(1+4\cos A)\]

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