## anonymous 5 years ago A rock of mass 10 kg sits on a slope which makes an angle of 25 degrees with the horizontal. If it does not slip down what is the magnitude of the frictional force?

1. anonymous

The weight of the rock is 98 N, so the component that is parallel to the slope would be $98*\sin(25degrees)\approx41.4N$ Thus the friction force must also be 41.4 N (or maybe just 41, because of significant figures)

2. anonymous

ok cool, thats what i ended up with, i just wasn't sure if it'd be that simple.