anonymous
  • anonymous
solve the intial value problem.. y' = (xy)^(1/2), y(0) = 1 how would you seperate x and y..??
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[{dy \over dx}=x^{1/2}y^{1/2} \implies {dy \over y^{1/2}}=x^{1/2}dx\]
anonymous
  • anonymous
Just integrate both sides, and then solve for the initial value.
anonymous
  • anonymous
oo i wasnt sure if we can pull them apart like that..

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