anonymous 5 years ago solve the intial value problem.. y' = (xy)^(1/2), y(0) = 1 how would you seperate x and y..??

1. anonymous

${dy \over dx}=x^{1/2}y^{1/2} \implies {dy \over y^{1/2}}=x^{1/2}dx$

2. anonymous

Just integrate both sides, and then solve for the initial value.

3. anonymous

oo i wasnt sure if we can pull them apart like that..